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Darya [45]
3 years ago
12

If the wavelength of a beam of light is decreased what happens to the momentum of the photons

Physics
1 answer:
chubhunter [2.5K]3 years ago
4 0

Answer: the momentum is increased

Energy and momentum are conserved, this was proved by he American physicist Arthur H. Compton after his experiments related to the scattering of photons from electrons (Compton Effect), in which he also proved that photons do have momentum.

So, this momentum p is given by the following expression:

p=\frac{h}{\lambda}

Where h is the Planck constant and \lambda is the wavelength of the photon.

As we can see, the momentum is inversely proportional to to the wavelength. This means, if \lambda <u>decreases</u>, p <u>increases</u>.

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1. Sang Hee rubs a balloon on her hair until, when she holds the balloon several inches from
vodomira [7]

The reason why Kim's hair rises and sticks out is due to electrostatic attraction.

<h3>What is charging by friction?</h3>

We know that one of the ways in which a body is able to acquire static charges is by friction. When a body is rubbed against another, there could be loss or gain of charges leaving a net charge on each body.

The process that occurs when some of Kim's hair rises and sticks out toward the balloon, even though the balloon hasn't touched her hair is electrostatic attraction.

Learn more about charging by friction:brainly.com/question/9201910

#SPJ1

7 0
2 years ago
Peter designed a road with a curve of radius 30 m that is banked so that a 950 kg car traveling at 40.0 km/h can round it even i
spayn [35]

Answer:

v = 15.56 m/s

v = 56 km/h

Explanation:

When coefficient of friction is approximately zero then we have

F_ncos\theta = mg

F_n sin\theta = \frac{mv^2}{R}

tan\theta = \frac{v^2}{Rg}

here we know that

v = 40 km/h = 11.11 m/s

R = 30 m

tan\theta = \frac{11.11^2}{30\times 9.81}

\theta = 22.75 degree

now when friction coefficient is 0.30 then we have

F_n cos\theta = mg + F_f sin\theta

F_f cos\theta + F_n sin\theta = \frac{mv^2}{R}

now we have

v = \sqrt{Rg(\frac{\mu + tan\theta}{1 - \mu tan\theta})}

v = \sqrt{30(9.81)(\frac{0.30 + tan22.75}{1 - (0.30) tan22.75})}

v = 15.56 m/s

v = 56 km/h

3 0
3 years ago
What is/are the products in the chemical equation?
Alla [95]

Answer:NH3

Explanation: product s are the result of the equation

5 0
3 years ago
Read 2 more answers
Which road would exert the LEAST amount of friction on a car?
bearhunter [10]

Answer:

Icy roads

Explanation:

There is so little friction you slide on it way more than other roads. :)

6 0
3 years ago
HELLO , PLZ HELP .
sergey [27]

Answer:

the pressure due to the water on the diver is 200,000 pascal

pressure = height × density × acceleration due to gravity

p = 20×1000×10

p=200,000 pascal

6 0
3 years ago
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