Determine the molarity for the fixer Sodium carbonate decahydrate (I dissolved 127.62 grams of sodium carbonate for every 4 lite
rs of water)
1 answer:
Answer:
0.112 M.
Explanation:
- Molarity is the no. of moles of solute in a 1.0 L of the solution.
M = n/V.
<em>M = (mass/molar mass)solute x (1000/V of the solution).</em>
mass = 127.62 g.
molar mass = 286.138 g/mol.
V of the solution = 4.0 L = 4000.0 mL.
<em>∴ M = (mass/molar mass)solute x (1000/V of the solution)</em> = (127.62 g / 286.138 g/mol) x (1000 / 4000.0 mL) = <em>0.1115 M ≅ 0.112 M.</em>
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Here we go ~
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has 6.022 × 10²³ molecules of the given compound.
So, 0.78 mole of
will have ~


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