Determine the molarity for the fixer Sodium carbonate decahydrate (I dissolved 127.62 grams of sodium carbonate for every 4 lite rs of water)
1 answer:
Answer:
0.112 M.
Explanation:
Molarity is the no. of moles of solute in a 1.0 L of the solution. M = n/V.
<em>M = (mass/molar mass)solute x (1000/V of the solution). </em>
mass = 127.62 g.
molar mass = 286.138 g/mol.
V of the solution = 4.0 L = 4000.0 mL.
<em>∴ M = (mass/molar mass)solute x (1000/V of the solution) </em> = (127.62 g / 286.138 g/mol) x (1000 / 4000.0 mL) = <em>0.1115 M ≅ 0.112 M. </em>
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