The equation of the ellipse in <em>standard</em> form is (x + 3)² / 100 + (y - 2)² / 64 = 1. (Correct choice: B)
<h3>What is the equation of the ellipse associated with the coordinates of the foci?</h3>
By <em>analytical</em> geometry we know that foci are along the <em>major</em> axis of ellipses and beside the statement we find that such axis is parallel to the x-axis of Cartesian plane. Then, the <em>standard</em> form of the equation of the ellipse is of the following form:
(x - h)² / a² + (y - k)² / b² = 1, where a > b (1)
Where:
- a - Length of the major semiaxis.
- b - Length of the minor semiaxis.
Now, we proceed to find the vertex and the lengths of the semiaxes:
a = 10 units.
b = 8 units.
Vertex
V(x, y) = 0.5 · F₁(x, y) + 0.5 · F₂(x, y)
V(x, y) = 0.5 · (3, 2) + 0.5 · (- 9, 2)
V(x, y) = (1.5, 1) + (- 4.5, 1)
V(x, y) = (- 3, 2)
The equation of the ellipse in <em>standard</em> form is (x + 3)² / 100 + (y - 2)² / 64 = 1. (Correct choice: B)
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D is the answer
(4+8)+1 = 13
4+(8+1) = 13
Therefore equation D is true
Answer:
A = 50.26 sq meters
Step-by-step explanation:
we have to find the diameter first by using the circumference:
C = πd
25.12 = πd
25.12/π = d
8 = d
this means the radius is 4
A = πr²
A = π4² or 16π
A = 50.26 sq meters
Answer:
70
Step-by-step explanation:
700 / 10 = 70
If we have
y = 6x + 1 and x - y = 11, we can take advantage of y - y = 0 as follows:
Subtract x from both sides of the 2nd equation:
-y = 11 - x
Now combine
y = 6x + 1
-y = 11 - x
--------------
0 = 5x + 12. Solving for x, x = -12/5. Using the equation above, find y:
-y = 11 - x
= 11 - (-12/5)
= 55/5 + 12/5 = 67/5
Then the solution is (-12.5, 67/5).
