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lana66690 [7]
3 years ago
6

What 3 simple machines are in scissors

Physics
1 answer:
fgiga [73]3 years ago
6 0
Lever I believe when you pull up and down in the handels
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Please help I'm confused on where to start and with the graph.
tankabanditka [31]

I don't think anyone knows the answer

3 0
3 years ago
Is it possible for an object to be going 100 miles per hour but have a velocity of zero?
Lesechka [4]
It is possible for on object to be going at 100 miles per hour, but still have a velocity. This is because the object going at 100 miles per hour has speed, which is a scalar quantity, which is defined by only magnitude, but the velocity of the object can be 0, since velocity is a vector quantity which is defined by both magnitude and direction.

Since this object only has magnitude and no direction (which is not given), then the velocity can be 0
5 0
3 years ago
Kristen has two identical sized cubes, one is lead (Pb) and one is copper (Cu). Kristen is determining the density of each cube.
natta225 [31]

Answer:

volume

Explanation:

Identical size means volume will be the same in each calculation of

density =   mass / <u>volume</u>

3 0
2 years ago
A spring stretches 0.018 m when a 2.8-kg object is suspendedfrom its end. How much mass should be attached to this spring sothat
agasfer [191]

Answer:

m = 4.29 kg

Explanation:

Given that,

Mass of the object, m = 2.8 kg

Stretching in the spring, x = 0.018 m

Frequency of vibration, f = 3 Hz

Let m is the mass of the object that is attached to the spring. When it is attached the gravitational force is balanced by the force on spring. It is given by :

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{2.8\times 9.8}{0.018}

k = 1524.44 N/m

Since, \omega=\sqrt{\dfrac{k}{m}}

m=\dfrac{k}{4\pi^2 f^2}

m=\dfrac{1524.44}{4\pi^2 \times 3^2}

m = 4.29 kg

So, the mass that is attached to this spring is 4.29 kg. Hence, this is the required solution.

4 0
3 years ago
NEED HELP ASAP!! Will give Brainliest.
olga2289 [7]

a. 25 joules of work is done by the object.

Explanation:

According to the work-energy theorem, the work done ON an object is equal to the change in kinetic energy of the object, therefore:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the car, with

m = 2 kg being the mass of the car

v = 0 is the final speed of the car (brought to rest)

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the car, with

u = 5 m/s being the initial speed of the car

Substituting numbers, we find:

W=\frac{1}{2}(2)(0)^2 - \frac{1}{2}(2)(5)^2=-25 J

The negative sign means that the work done ON the car is negative: this means therefore that the work has been actually done BY the car. In fact, the car has lost its kinetic energy: this means that it has done work on the surrounding, converting its kinetic energy into other forms of energy.

Learn more about work and kinetic energy:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/6536722

#LearnwithBrainly

5 0
3 years ago
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