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lana66690 [7]
3 years ago
6

What 3 simple machines are in scissors

Physics
1 answer:
fgiga [73]3 years ago
6 0
Lever I believe when you pull up and down in the handels
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Which demonstrates conduction?
wariber [46]
Cool feet walking across the hot pavement is correct bc they touch or make contact  <span />
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A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center
Bess [88]

Answer:

10.93 rad/s

Explanation:

If we treat the student as a point mass, her moment of inertia at the rim is

I_r = mr^2 = 67.8*3.7^2 = 928.182 kgm^2

So the system moment of inertia when she's at the rim is:

I_1 = I_d + I_r = 274 + 928.182 = 1202.182 kgm^2

Similarly, we can calculate the system moment of inertia when she's at 0.456 m from the center

I_2 = I_d + 67.8*0.456^2 = 274 + 14.1 = 288.1 kgm^2

We can apply the law of angular momentum conservation to calculate the post angular speed when she's 0.456m from the center:

I_1\omega_1 = I_2\omega_2

\omega_2 = \omega_1\frac{I_1}{I_2} = 2.62*\frac{1202.182}{288.1} = 10.93 rad/s

8 0
3 years ago
Synonym of an applied force
tatuchka [14]

Answer:

Coerce, compel, constrain

Explanation:

7 0
3 years ago
(a) Calculate the magnitude of the gravitational force exerted by Mars on a 80 kg human standing on the surface of Mars. (The ma
andrew11 [14]

Answer:

a) F=1.044\times 10^9\ N

b)F'=1.044\times 10^9\ N

c) F_p=1.0672\times10^{-7}\ N

d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

  • mass of Mars, M=6.4\times 10^{23}\ kg
  • radius of the Mars, r=3.4\times 10^{6}\ m
  • mass of human, m=80\ kg

a)

Gravitation force exerted by the Mars on the human body:

F=G.\frac{M.m}{r^2}

where:

G=6.67 \times 10^{-11}\ m^3.kg^{-1}.s^{-2} = gravitational constant

F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}

F=1.044\times 10^9\ N

b)

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

F'=F

F'=1.044\times 10^9\ N

c)

When a similar person of the same mass is standing at a distance of 4 meters:

F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}

F_p=1.0672\times10^{-7}\ N

d)

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

  • Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
  • Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
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3 years ago
Which of the following biomes might be found at a latitude of 33° South?
cupoosta [38]
The answer is going be desert. 
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