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kirill [66]
3 years ago
13

Hey i rlly need help with these math problems plsss hurry plss answer all there are 5 questions

Mathematics
1 answer:
Mila [183]3 years ago
3 0

Answer:

for one its 14x+18

for two its -11x-21

for three its x=12

for four its x=-12

for five x=11/7

Step-by-step explanation:

i hope this helps u

btw like i can see your school in the taskbar so next time just crop that out lol

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What is the difference between an irrational number and an integer?? please explain!
SpyIntel [72]

Answer:

Explanation: Irrational numbers are non-terminating, recurring decimal numbers i.e, a decimal expansion that neither terminates nor becomes periodic which cannot be expressed in the form of a fraction. ... Integer is a complete entity that includes every natural number along with its negatives and zero.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Evaluate.<br><br> 4^3−4÷2⋅5<br><br><br> 20<br><br> 40<br><br> 54<br><br> 150
nika2105 [10]

Answer:

150

Step-by-step explanation:

1. 4^3 = 4 x 4 x 4 = 16 x 4 = 64

2. 64 - 4 = 60

3. 60 ÷ 2 = 30

4. 30 ⋅ 5 = 150

3 0
3 years ago
The quadrilateral shown is rotated 90° clockwise about the origin. In which quadrant is the image of the quadrilateral located?
Viktor [21]

Answer:

Option (2). 1

Step-by-step explanation:

Coordinates of point A, B, C and D are,

A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).

Quadrilateral ABCD when rotated 90° clockwise about the origin,

Rule for the rotation of the vertices,

(x, y) → (y, -x)

Following the rule of rotation coordinates of the image points,

A(-4, 4) → A'(4, 4)

B(-2, 4) → B'(4, 2)

C(-2, 1) → C'(1, 2)

D(-4, 3) → D'(3, 4)

Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.

Option (2) is the correct option.

4 0
3 years ago
What is the absolute value of 2 1/3
taurus [48]
2/12 is the correct answer
3 0
3 years ago
Read 2 more answers
A club has 10 members.
TEA [102]
That is the combination of 10 over 3, which is calculated as the quotient of factorials:
n!/k!(n-k)!
where n = 10 and k = 3:
= 10!/3!(10 - 3)!
= 10!/3!*7!
= (10*9*8)/(3*2*1)
= 720/6
= 120
therefore there a re 120 possible different groups
6 0
3 years ago
Read 2 more answers
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