4.1 h = 14760 s
<span>t 1/2 = ln 2 / k </span>
<span>k = rate reaction = 4.97 x 10^-5 </span>
<span>ln 0.045 / 0.36 = - 4.97 x 10^-5 t </span>
<span>2.08 = 4.97 x 10^-5 t </span>
<span>t = 41839.9 s = 11 h 37 min 19 s</span>
John Dalton
Although the concept of the atom dates back to the ideas of Democritus, the English meteorologist and chemist John Dalton formulated the first modern description of it as the fundamental building block of chemical structures.
Answer:
17.5 g/cm³
Explanation:
We can solve this particular problem by keeping in mind the <em>definition of density</em>:
As the problem gives us both <em>the mass and the volume</em> of the box, we can now proceed to <u>calculate the density</u>:
The density of the box is 17.5 g/cm³.
The reaction is of order three with respect to the reactant.
<h3>Explanation</h3>
The rate of a reaction of order n about a certain reactant is proportion to the concentration of that reactant raised to the n-th power. This is true only if concentrations of any other reactants stay constant in the whole process.
In other words, Rate = constant × [Reactant]ⁿ, Rate ∝ [Reactant]ⁿ. (The symbol "∝" reads "proportional to".)
In this question,
[4 × Reactant]ⁿ ÷ [Reactant]ⁿ = 64.
In other words, 4ⁿ = 64, where n is the order of the reaction with respect to this reactant.
It might take some guesswork to find the value of n. Alternatively, n can be solved directly with a calculator using logarithms. Taking natural log of both sides:
.
Evaluating
on Google or on a calculator with support for ln (the natural log) will give the value of n- no guesswork required.
n = 3. Therefore, the reaction is of order three with respect to this reactant.
Answer:
Do you have a picture?
Explanation:
Sometimes, pictures are required to answer questions.