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Leona [35]
2 years ago
11

2. HBIO3 name this acid.​

Chemistry
1 answer:
aleksandr82 [10.1K]2 years ago
3 0

Answer:

Hydroxy(oxo)bismuthine oxide

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Writing Chemical Equations
nignag [31]

Answer:    

The prefix di means 2 and the prefix hexa means 6.

As per IUPAC rules you must use the prefixes to indicate the number of atoms of each element in the formula.

So, the proper name for the compound C2H6 is dicarbon hexahydride.

Explanation:

8 0
2 years ago
Uranium-267 undergoes alpha decay, what is the mass of the new element?
Firlakuza [10]

Answer:

will this help ?

Explanation:

(108Hs) is a synthetic element, and thus a standard atomic weight cannot be given. Like all synthetic elements, it has no stable isotopes. The first isotope to be synthesized was 265Hs in 1984. There are 12 known isotopes from 263Hs to 277Hs and 1–4 isomers. The most stable isotope of hassium cannot be determined based on existing data due to uncertainty that arises from the low number of measurements. The confidence interval of half-life of 269Hs corresponding to one standard deviation (the interval is ~68.3% likely to contain the actual value) is 16 ± 6 seconds, whereas that of 270Hs is 9 ± 4 seconds. It is also possible that 277mHs is more stable than both of these, with its half-life likely being 110 ± 70 seconds, but only one event of decay of this isotope has been registered as of 2016.[1][2].

3 0
2 years ago
Could an organism survive without its mitochondria if all the other organelle were present
lisov135 [29]
No, <span>mitochondria convert the sugar, can give it(the cell) Nutrients (food) to mainly keep it fresh and alive. Without cells mitochondria can't do its job.</span>
8 0
3 years ago
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How many particles are in 47.7 g of Magnesium? (Round the average
Lynna [10]

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

47.7 g Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

<u>Step 3: Convert</u>

<u />47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} ) = 1.18161 × 10²⁴ particles Mg

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

3 0
2 years ago
What is the identity of the atom shown?
Charra [1.4K]
The answer is a , as aluminium has 13 protons and electrons .
6 0
3 years ago
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