The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.

For reaction :

$\tt aA+bB\rightarrow cC+dD$

The rate reaction :

$\tt -\dfrac{1}{a}\dfrac{d[-A]}{dt}= -\dfrac{1}{b}\dfrac{d[-B]}{dt}=\dfrac{1}{c}\dfrac{d[C]}{dt}=\dfrac{1}{d}\dfrac{d[D]}{dt}$

Reaction for formation CCl₄ :

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From equation, rate of reaction = rate of formation CCl₄ = 0.05 mol/dm³

Rate of formation of CCl₄ = reaction rate x coefficient of CCCl₄

0.05 mol/dm³ = reaction rate x 1⇒reaction rate = 0.05 mol/dm³

The rate of disappearance of chlorine gas (Cl₂) :

Rate of disappearance of Cl₂ = reaction rate x coefficient of Cl₂

Rate of disappearance of Cl₂ = 0.05 x 4 = 0.2 mol/dm³

4 0

3 years ago

If a tank of gas contains 4 L of N O2 how many molecules are in it

Jobisdone [24]

but heres a way to solve it

An athlete takes a deep breath, inhaling 1.85 L of air at 21°C and 754 mm Hg.

How many moles of air are in the breath? How many molecules?

Gas constant, R= 8.314 J mol ¹ K-1

PV = nRT

= 0.08206 L atm mol-1 K-1

= 62.36 L Torr mol-1 K-1 -

1 atm = 760 mm Hg = 760 Torr

754 Forr 1.85€

6236 Jerr 294K

3 0

2 years ago

The half life of Radon-222 is 3.8 days. If you have a 90.0g sample of Radon-222 in the lab, how much will be left after 19 days?

statuscvo [17]

Answer:

half lives passed=5

given sample=90g

sample left=2.8125g

Explanation:

no. of half lives=total time/half life

no.=19days/3.8days

no.=5 days

after 5 half lives sample left=2.8125g

5 0

3 years ago

The half-life of barium-131 is 12.0 days. How many grams of

dimulka [17.4K]

Let's see

$\\ \rm\Rrightarrow A=A_o(0.5)^{\frac{t}{H}}$

H is half-life

$\\ \rm\Rrightarrow A=10(0.5)^{\frac{60}{12}}$

$\\ \rm\Rrightarrow A=10(0.5)^5$

$\\ \rm\Rrightarrow A=10(0.03125)$

$\\ \rm\Rrightarrow A=0.3125g$

3 0

2 years ago

2. HBIO3 name this acid.​

2. HBIO3 name this acid.