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natita [175]
3 years ago
14

A recent study has revealed that chlorinated hydrocarbons, gasoline and other volatile organic compounds (VOC's) have become sig

nificant pollutants in ________ from ________.
Chemistry
1 answer:
Sedaia [141]3 years ago
5 0

Answer:

ground water / leaking storage tanks

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konstantin123 [22]
The awnser is D or the 4th one
6 0
3 years ago
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Acetone is one of the most important solvents in organic chemistry. It is used to dissolve everything from fats and waxes to air
Phantasy [73]

Answer:

The half-life time, the team equired for a quantity to reduce to half of its initial value, is 79.67 seconds.

Explanation:

The half-life time = the time required for a quantity to reduce to half of its initial value. Half of it's value = 50%.

To calculate the half-life time we use the following equation:

[At]=[Ai]*e^(-kt)

with [At] = Concentration at time t

with [Ai] = initial concentration

with k = rate constant

with t = time

We want to know the half-life  time = the time needed to have 50% of it's initial value

50 = 100 *e^(-8.7 *10^-3 s^- * t)

50/100 = e^(-8.7 *10^-3 s^-1 * t)

ln (0.5) = 8.7 *10^-3 s^-1 *t

t= ln (0.5) / -8.7 *10^-3  = 79.67 seconds

The half-life time, the team equired for a quantity to reduce to half of its initial value, is 79.67 seconds.

4 0
3 years ago
What is the overall cell potential for this redox reaction? Ca2+ + 2Li = Ca + 2Li+ Ca2+ + 2e- = Ca -2.87 V Li = Li+ + e- -3.05 V
Jet001 [13]

The redox reaction is

Ca^{+2}  + 2Li(s)  = Ca(s) + 2Li^{+}

Here

Calcium undergoes reduction, and acts as cathode

Lithium undergoes oxidation and acts as anode

The reduction potential of calcium is -2.87 V

The reduction potential of lithium is - -3.05 V

We know that

Ecell = Ecathode - Eanode

Ecell = -2.87 - (-3.05)  = 0.18 V


4 0
3 years ago
Most chemical reactions take place in labs true or false
arsen [322]
The answer would most likely be False
7 0
3 years ago
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what is the work done by a bird pulling a worm from the dirt with a force of .05 N and a distance of .07 m
masya89 [10]
Hello!

Work=Force*Displacment

Work=.05N * .07m = .0035J

Any questions please feel free to ask. Thank you.
5 0
3 years ago
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