The enthalpy of formation has a negative sign, which means that the reaction is exothermic. In other words, when ethanol is formed, heat is released to the surroundings as a by-product. The reaction for the formation of ethanol is written below:
<em>C₂H₄ + H₂O → C₂H₅OH</em>
Km -> mi = km/1.6
So 11.3/1.6 = <span>7.0625mi/s exit speed
<span>3600 seconds in an hour
</span></span><span>7.0625*3600 = 25425 mph<span><span><span><span>
</span></span></span></span></span>
Answer:
0.57 moles (NH4)3PO4 (2 sig. figs.)
Explanation:
To quote, J.R.
"Note: liquid ammonia (NH3) is actually aqueous ammonium hydroxide (NH4OH) because NH3 + H2O -> NH4OH.
H3PO4(aq) + 3NH4OH(aq) ==> (NH4)3PO4 + 3H2O
Assuming that H3PO4 is not limiting, i.e. it is present in excess
1.7 mol NH4OH x 1 mole (NH4)3PO4/3 moles NH4OH = 0.567 moles = 0.57 moles (NH4)3PO4 (2 sig. figs.)"
I would agree with the second one, not the first. You can't always see the chemical reaction, and it isn't always sudden. But the second claim is true.
