Answer: B
Refer:
Because water molecules are polar, they interact with the sodium and chloride ions. In general, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes. This concept is often expressed as “Like dissolves like.
Answer:
Aluminum is the 13th element on the periodic table. It is located in period 3 and family 13.
Explanation:
Answer:
See explanation
Explanation:
A dipole refers to a bond in which its two ends have opposite charges. A dipole results from a large difference in electronegativity between two atoms in a bond.
For instance, consider the bond between hydrogen and chlorine in HCl. The electronegativity of hydrogen is 2.2 while that of chlorine is 3.16. The significant electronegativity difference between the two atoms leads to a charge separation.
A partial positive charge appears on the atom that is less electronegative (hydrogen) while a negative charge appears on the more electronegative atom (chlorine).
This charge separation occurs because the shared electrons of the bond are more closely attracted to chlorine making it partially negative compared to hydrogen. A dipole moment now exists in the H-Cl bond hence the molecule is said to have a dipole.
Okay to separate this mixture you will have to first use a magnet because the magnet will attract the iron filings out of the sand then you will remain with the sand and salt.
Next step is to add water to the sand and salt mixture the salt will dissolve in the water and the sand will not forming a heterogeneous mixture.Then using the method of filtration you can separate the sand from the salt solution leaving the salt solution
To separate the salt from the water use the method of evaporation this will enable you to get back the salt
In the end you should beable to have the sand,salt and iron filings separate.
Hope this was helpful to you.
Happy New Years !!! May your year be prosperous
Answer:
1/32 of the original sample
Explanation:
We have to use the formula
N/No = (1/2)^t/t1/2
N= amount of radioactive sample left after n number of half lives
No= original amount of radioactive sample present
t= time taken for the amount of radioactive samples to reduce to N
t1/2= half-life of the radioactive sample
We have been told that t= five half lives. This implies that t= 5(t1/2)
N/No = (1/2)^5(t1/2)/t1/2
Note that the ratio of radioactive samples left after time (t) is given by N/No. Hence;
N/No= (1/2)^5
N/No = 1/32
Hence the fraction left is 1/32 of the original sample.
