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2 years ago

Florian is testing some household supplies with red and blue litmus paper. The results are in the table below.

Chemistry

2 answers:

Savatey [412]2 years ago

8 0

Answer:

Glass cleaner is BASIC.

Aspirin is ACIDIC.

Sugar water is NEUTRAL.

Bess [88]2 years ago

7 0

Answer:

1:Basic /2: acidic/ 3: neutral

Explanation:

IDK

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A chemist adds of a potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate t

boyakko [2]

Answer:

3.41 g

Explanation:

A chemist adds 260.0 mL of a 0.0832M potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate the chemist has added to the flask. Round your answer to 3 significant digits.

Step 1: Given data

Volume of the solution (V): 260.0 mL (0.2600 L)

Concentration of the solution (C): 0.0832 M (0.0832 mol/L)

Step 2: Calculate the moles (n) of potassium permanganate added

We will use the following expression.

n = C × V

n = 0.0832 mol/L × 0.2600 L = 0.0216 mol

Step 3: Calculate the mass corresponding to 0.0216 moles of potassium permanganate

The molar mass of potassium permanganate is 158.03 g/mol.

0.0216 mol × 158.03 g/mol = 3.41 g

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2 years ago

What volume and mass of steam at 100. °C and 1.00 atm would release the same amount of energy during condensation as 100. cm^3 o

viva [34]

Check on google and make it a question Maybe itll appear

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2 years ago

a 1.00-l solution contains 2.50×10-4 m cu(no3)2 and 1.20×10-3 m ethylenediamine (en). the kf for cu(en)22 is 1.00 × 1020. chegg

Debora [2.8K]

The concentration of copper in the solution is

$5.1 \times 10^{18} \: M.$

The volume of the solution = 1.00 L

$Moles \: of \:Cu(NO_{3}) _{2} = 2.50 \times 10 {}^{ - 4}$

$Moles \: of \: Ethylenediamine = 1.20 \times 10.3$

$k _{f} = 1.00 \times 10^{20}$

Overall balanced equation of reaction is,

$Cu^{2 + }(aq) \: + 2en \: (aq)→ Cu(en) ^{2 + }_{2}(aq)$

$Moles \: of \:Cu(NO_{3}) _{2} =0.00025 \: mol$

Mole ratio for,

$Moles \: of\:Cu(NO_{3}) _{2}: en$

$2: 1$

$Moles \: of \: en = 0.000250 \times 2$

$= 0.00050 \: moles$

Remained moles of en are= (0.00120-0.000500)

$= 0.000700 \: moles$

The concentration of copper in the solution is,

$k_{f} = \frac{Cu(en)^{2 + }_{2} }{Cu^{2+}en^{2} }$

$1.00 \times 10 ^{20} = \frac{0.000250}{(Cu )^{2 +} \times (0.000700)^{2 + } }$

$= 5.1 \times 10^{18} \: M.$

Therefore, the concentration of copper in the solution is

$5.1 \times 10^{18} \: M.$

To know more about molarity, refer to the below link:

brainly.com/question/8732513

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1 year ago

What gas makes up the majority of the Earth's atmosphere?

Naya [18.7K]

Answer:

Nitrogen and oxygen are by far the most common; dry air is composed of about 78% nitrogen (N 2) and about 21% oxygen (O 2).

In short, Nitrogen

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2 years ago

I need help asap why is there only one variable in an experiment that changes?

tekilochka [14]

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