Question

Calculate the molar mass of Ca3(PO4)2 934.32 g Ca3(PO4)2 =______ moles Ca3(PO4)2

Answer 1

Answer:

• Molar mass of Ca₃(PO₄)₂ = 310.18 g/mol

• 934.32 g Ca₃(PO₄)₂ = 3.01 moles Ca₃(PO₄)₂

Explanation:

The molar mass (MM) of Ca₃(PO₄)₂ can be calculated as follows:

• MM of Ca₃(PO₄)₂ = (MM of Ca)*3 + [(MM of P) +(MM of O)*4]*2

• MM of Ca₃(PO₄)₂ = 310.18 g/mol

Now we can convert 934.32 g of Ca₃(PO₄)₂ into moles:

• 934.32 g ÷ 310.18 g/mol = 3.01 moles