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stealth61 [152]
2 years ago
13

Show that the speed of an electron in the nth bohr orbit of hydrogen is αc/n, where α is the fine structure constant. what wou

ld be the speed in a hydrogen-like atom with a nuclear charge of ze?
Chemistry
1 answer:
PtichkaEL [24]2 years ago
4 0
<span>In the Bohr model we assume that angular momentum is quantised: L = mvr = nℏ From this you can find the expression for the tangential velocity of the electron. You then need to find the expression for the Bohr radius for a particular value of n, which turns out to be (for Z = 1, for Hydrogen-like atoms just replace e^2 with Z(e^2)): rn=4πϵ0ℏ2n2/me2 When you sub in for r you get: vn=e2/4πϵ0ℏ From this you should be able to work out what the fine structure constant is - just compare the equation you were given to the one above. In undergrad physics courses the name "fine structure constant" is often applied to a few dimensionless constants that all look similar. It's just a number that happens to arise in a lot of Quantum Mechanical situations.</span>
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3 0
3 years ago
A car with a mass of 1,500 kg is traveling at a speed of 30 m/s. What force must be applied to stop the car in 3 seconds ?
saw5 [17]

Yo sup??

we can solve this problem by applying Newton's 2nd law

F*t=Δp

p=momentum

pi=mu=1500*30

pf=mv=m*0=0

Therefore

F*3=1500*30

F=15000 N

Hope this helps.

5 0
2 years ago
if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?
ipn [44]

Answer:

M of HI = 5.4 M.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

<em>(XMV) acid = (XMV) base.</em>

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HI = (XMV) Ca(OH)₂.</em>

For HI; X = 1, M = ??? M, V = 25.0 mL.

For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.

<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>

6 0
3 years ago
This diagram shows the shift in the spectrum for hydrogen light from several different sources in the universe compared to a lab
Artyom0805 [142]

Answer:

Many stars and distant galaxies move at varying speeds compared to each other.

Explanation:

All statements are contradictory, so play it safe and declare different energy levels.

8 0
2 years ago
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Answer:

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Explanation:

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8 0
2 years ago
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