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Elza [17]
2 years ago
8

A 65 kg woman is horizontal in a push-up position. What are the vertical forces acting on her hands?​

Physics
1 answer:
Leni [432]2 years ago
8 0

Answer:

Explanation:

Sum moments about her toes, to zero.

65(9.8)[1.00] - F[1.50] = 0

F = 424.666... N

Rounding to two significant digits makes it

F = 420 N

Don't know what to tell you, None of those options seem really close and you have two options at 410.4 N so I'm guessing a typo.

If you only take a single significant digit on gravity to make it 10 m/s² you end up with answer B), but why would one assume four significant digits in an answer when only a single significant digit went into the arguments? Only thing we can say for certain is it's probably not C)

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Calculate the orbital period for Jupiter's moon Io, which orbits 4.22×10^5km from the planet's center (M=1.9×10^27kg) .
Verdich [7]

According to the <u>Third Kepler’s Law of Planetary motion</u> “<em>The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>



In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size a of its orbit.



This Law is originally expressed as follows:



<h2>T^{2} =\frac{4\pi^{2}}{GM}a^{3}    (1) </h2>

Where;


G is the Gravitational Constant and its value is 6.674(10^{-11})\frac{m^{3}}{kgs^{2}}



M=1.9(10^{27})kg is the mass of Jupiter


a=4.22(10^{5})km=4.22(10^{8})m  is the semimajor axis of the orbit Io describes around Jupiter (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)



If we want to find the period, we have to express equation (1) as written below and substitute all the values:



<h2>T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}    (2) </h2>

T=\sqrt{\frac{4\pi^{2}}{6.674(10^{-11})\frac{m^{3}}{kgs^{2}}1.9(10^{27})kg}(4.22(10^{8})m)^{3}}    



T=\sqrt{\frac{2.966(10^{27})m^{3}}{1.268(10^{17})m^{3}/s^{2}}}    



T=\sqrt{2.339(10^{10})s^{2}}    



Then:


<h2>T=152938.0934s    (3) </h2>

Which is the same as:



<h2>T=42.482h     </h2>

Therefore, the answer is:



The orbital period of Io is 42.482 h



7 0
3 years ago
Why does a plastic comb attract small bits of paper after rubbing with wool?
navik [9.2K]
Static electricity. Like the balloon against hair
5 0
3 years ago
7. Two bikes travelling in the same direction move at a speed of 30 km/hr. The bikes are separated by a distance of 5 km. What w
Fantom [35]

Answer:

Explanation:

Call the bike on the right A

Call the bike on the left B

The car begins it's time when it passes A

4 minutes later, it passes B.

But B has moved in 4 minutes and that is the key to the problem.

How far has B moved.

t = 4 minutes = 4/60 hours = 1/15 of an hour.

d = ?

rate = 30 km / hr

d = r * t

d = 30 km/hr * 1/15 hours = 2 km

The distance between the bikes is 5 km.

So the car has traveled 5 - 2 = 3 km

d = 3 km

r = ?

t = 4 minutes = 1/15 hour

r = d/t = 3/(1/15)= 3 / 0.066666666  = 45 km/hr.

6 0
3 years ago
An object falling straight down without air resistance is said to be exhibiting
Tanzania [10]

Answer:

Explanation:

If the object is falling straight down it is in free fall.  The difference between that and two-dimensional motion is that 2D motion is parabolic (projectile)

6 0
3 years ago
How many hydrogen atoms are there in one molecule of PH3?
galben [10]

Answer:

On molecules of PH3, there has to be 3 atoms.

Explanation:

The Element Hydrogen (H) has 3 attoms.

The Element Phosphorus (P) has 1 atom.

These two created into the molecule PH3, would have to have only 3 attoms because they are asking how many hydrogens atoms are in the molecule PH3.    

7 0
3 years ago
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