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Elza [17]
2 years ago
8

A 65 kg woman is horizontal in a push-up position. What are the vertical forces acting on her hands?​

Physics
1 answer:
Leni [432]2 years ago
8 0

Answer:

Explanation:

Sum moments about her toes, to zero.

65(9.8)[1.00] - F[1.50] = 0

F = 424.666... N

Rounding to two significant digits makes it

F = 420 N

Don't know what to tell you, None of those options seem really close and you have two options at 410.4 N so I'm guessing a typo.

If you only take a single significant digit on gravity to make it 10 m/s² you end up with answer B), but why would one assume four significant digits in an answer when only a single significant digit went into the arguments? Only thing we can say for certain is it's probably not C)

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A depiction of a famous scientific experiment is given. Consider how the beam changes when the magnet is off compared to when th
iogann1982 [59]

Answer:

The beam used is a negatively charged electron beam with a velocity of

v = E / B

Explanation:

After reading this long statement we can extract the data to work on the problem.

* They indicate that when the beam passes through the plates it deviates towards the positive plate, so the beam must be negative electrons.

* Now indicates that the electric field and the magnetic field are contracted and that the beam passes without deviating, so the electric and magnetic forces must be balanced

           F_{e} =  F_{m}

           q E = qv B

           v = E / B

this configuration is called speed selector

They ask us what type of beam was used.

The beam used is a negatively charged electron beam with a velocity of v = E / B

6 0
3 years ago
An infinitely long cylindrical insulating shell of inner radius a and outer radius b has a uniform volume charge density p. Dete
xenn [34]

Answer: The electric field is: a) r<a , E0=; b) a<r<b E=ρ (r-a)/εo;

c) r>b E=ρ b (b-a)/r*εo

Explanation: In order to solve this problem we have to use the Gaussian law in diffrengios regions.

As we know,

∫E.dr= Qinside/εo

For r<a --->Qinside=0 then E=0

for a<r<b er have

E*2π*r*L= Q inside/εo       in this case Qinside= ρ.Vol=ρ*2*π*r*(r-a)*L

E*2π*r*L =ρ*2*π*r* (r-a)*L/εo

E=ρ*(r-a)/εo

Finally for r>b

E*2π*r*L =ρ*2*π*b* (b-a)*L/εo

E=ρ*b* (b-a)*/r*εo

3 0
2 years ago
If a charge at 60c flow in a conductor for 30 second then the current that flow in a conductor is​
saw5 [17]

Explanation:

<h3>Given</h3>

- Charge = 60c

time = 30 sec

<h3>To find -</h3>

current

<h3>Solution </h3>

Current = Charge/time

I = V/T

I = 60/30

I = 2 ampere

More to know -

I = Current

V = Charge

T = Time

3 0
3 years ago
About how long does it take for sound to travel 1 Km?
viktelen [127]
It would take roughly 3 seconds.
4 0
3 years ago
What instrument uses a magnetic field to magnify imags up to 100000000?
Mariana [72]
Transmission electron microscope
5 0
2 years ago
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