Can someone please help with this problem?

Your bike gets a flat tire. Its mass is 10 kg and you are able to accelerate your bike .5 m/s/s. What is the force on the bike..

STALIN [3.7K]

Answer:

50N

Explanation:

Given parameters:

Mass of the bike = 10kg

Acceleration = 5m/s²

Unknown:

Force on the bike = ?

Solution:

To solve this problem, we apply Newton's second law of motion.

Force = mass x acceleration

Force = 10 x 5 = 50N

6 0

2 years ago

QUESTION: A study group of students is reviewing claims in an article that gamma rays are among the most dangerous type of elect

Lubov Fominskaja [6]

B

Bias is an inclination towards one way of thinking due to inherent factors in our environment, such as how one was brought up.

Explanation:

In science, biases, conscious or unconscious, tend to make experiments’ results to incline in particular way rather than being impartial. Peer- review of scientific journals by the scientific community is meant to be a quality assurance measure to detect such biases. The students should check reviews of the scientific community on the article and see if any biases have been pointed out. Probably the institution that the scientist works for is in competition with another institution that deals with gamma rays.

Learn More:

brainly.com/question/1903490

brainly.com/question/8480257

#LearnWithBrainly

4 0

3 years ago

Read 2 more answers

xIn the reaction A B + C + heat, ______. there is a net input of energy the potential energy of the products is greater than tha

kow [346]

Answer: Option (d) is the correct answer.

Explanation:

A chemical reaction in which heat energy is liberated is known as an exothermic reaction.

For example, $A \rightarrow B + C + Heat$

In an exothermic reaction, energy of reactants is more than the energy of products.

This means that potential energy of products is less than the potential energy of reactants.

Thus, we can conclude that in the reaction $A \rightarrow B + C + heat$ , the potential energy of the products is less than that of the reactant.

6 0

2 years ago

What is Newton's Second Law of Motion? (2 points) Every reaction is equal to the force applied. Forces are balanced when they ar

raketka [301]

Well, they're not quite the way Newton expressed it, but out of all this mess of statements, there are two that are correct AND come from Newton's 2nd Law of Motion:

-- The smaller the mass of an object, the greater the acceleration of that object when a force is applied.

-- The greater the force applied, the greater the acceleration.

For the other statements in the question:

-- Every reaction is equal to the force applied. True; comes from Newton's 3rd law of motion.

-- Forces are balanced when they are equal and opposite. True; kind of a definition, not from Newton's laws of motion.

-- An object at rest or in motion will remain at rest or in motion unless acted upon by an unbalanced force. True; comes from Newton's 1st law of motion.

5 0

2 years ago

A penny rides on top of a piston as it undergoes vertical simple harmonic motion with an amplitude of 4.0cm. If the frequency is

BlackZzzverrR [31]

Answer:

the penny loses contact at the piston's highest point.

f = 2.5 Hz

Explanation:

Concepts and Principles

1- Newton's Second Law: The net force F on a body with mass m is related to the body's acceleration a by

∑F = ma (1)

2- The maximum transverse acceleration of a particle in simple harmonic motion is found in terms of the angular speed w and the amplitude A as follows:

a_max = -w^2A (2)

3- The angular frequency w of a wave is related to the frequency f by:

w = 2π f (3)

Given Data

- The amplitude of the piston is: A = (4.0 cm) ( 1/ 100 cm)= 0.04 m.

- The frequency of oscillation of the piston is steadily increased.

Required Data

In part (a), we are asked to determine the point at which the penny first loses contact with the piston.

In part (b), we are asked to determine the maximum frequency for which the penny just barely remains in place for a full cycle.

Solution

(a)

The free-body diagram in Figure 1 shows the forces acting on the penny; mi is the gravitational force exerted by the Earth on the penny andrt is the normal contact force exerted by the piston on the penny.

figure 1 is attached

Apply Newton's second law from Equation (1) in the vertical direction to the penny:

∑F_y -mg= ma

Solve for n=m(g+a) The penny loses contact with the surface of the oscillating piston when the normal force n exerted by the piston is zero. So

0 = m(g + a)

a = —g

Therefore, the penny loses contact with the piston when the piston starts accelerating downwards. The piston first acceleratesdownward at its highest point and hence the penny loses contact at the piston's highest point.

(b)

The maximum acceleration of the penny at the highest point of the piston is found from Equation (2):

a = —w^2A

where a = —g at the highest point. So

g = w^2A

Solve for w:

w =√g/A

Substitute for w from Equation (3):

2πf = √g/A

Solve for f :

f = 1/2π√g/A

Substitute numerical values:

f = 1/2π√9.8 m/s^2/0.04

f = 2.5 Hz

6 0

3 years ago