All categories

3 years ago

Which form of heat transfer occurs when objects of two temperatures touch

Physics

1 answer:

Arada [10]3 years ago

7 0

Conducting because it occurs when two objects touch and heat is transferred

You might be interested in

Like his parents, Thomas is short, stocky, and heavyset. Although he exercises regularly and eats a well-balanced meal, his body

Viktor [21]

Answer:

Genetics?

Explanation:

8 0

3 years ago

Read 2 more answers

What happens to the force between two charges when each charge is doubled and the distance between them is 1/4 its original

DIA [1.3K]

Answer:

F' = 64 F

Explanation:

The electric force between charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

Where

q₁ and q₂ are charges

r is the distance between charges

When each charge is doubled and the distance between them is 1/4 its original magnitude such that,

q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)

New force,

$F'=\dfrac{kq_1'q_2'}{r'^2}$

Apply new values,

$F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F$

So, the new force becomes 64 times the initial force.

7 0

2 years ago

A projectile is launched with an initial velocity of 25m/s at 35 degrees above the horizontal. assuming that the projectile retu

Dovator [93]

Speed is the same as the initial: 25m/s.

*if* you need vectors though:

final velocity = (25*cos(35), -25*sin(35) ) m/s

3 0

3 years ago

Which of the following is not accurate when describing solids? A. Solids are better conductors of heat than liquids B. The amoun

Elza [17]

B. The amount of pressure exerted by a solid is solely dependent on its mass
i just took the test

3 0

3 years ago

Read 2 more answers

What is the energy of a mole of photons that have a wavelength of 413 nm? (h = 6.626 × 10⁻³⁴ J • s and c = 3.00 × 10⁸ m/s)

Triss [41]

Answer:

Energy of one mole of photon will be $2.89\times 10^5J$

Explanation:

We have given wavelength of photon $\lambda =413nm=413\times 10^{-9}m$

Velocity of light is given $c=3\times 10^8m/sec$

Plank's constant $h=6.626\times 10^{-34}Js$

Energy of the photon is given by $E=\frac{hc}{\lambda }=\frac{6.626\times 10^{-34}\times 3\times 10^8}{413\times 10^{-9}}=0.048\times 10^{-17}J$

We have to find the energy of one mole of photon

One mole of photon is equal to $6.023\times 10^{23}photon$

So energy of one mole of photon will be equal to $6.023\times 10^{23}\times 0.048\times 10^{-17}=2.89\times 10^5J$

So energy of one mole of photon will be $2.89\times 10^5J$

6 0

3 years ago