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2 years ago

Help? The question is down below.

Chemistry

2 answers:

Ne4ueva [31]2 years ago

7 0

I believe first one is T. The next one atoms are composed of smaller particles of matter so I think T. The third one is T. The fourth is T. The fifth might be false. And lastly atom is a small part of matter so false maybe. If that makes sense

Murrr4er [49]2 years ago

6 0

The first three are T I don’t know about the next two and the last one is T

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3 years ago

c3H8 + 5O2 = 3CO2 + 4H2O When 44.0 grams of propane (C3H8) under goes complete combustion, how many grams of water will be produ

Umnica [9.8K]

<u>Answer:</u> 72 grams of water will be produced.

<u>Explanation:</u>

To calculate the number of moles, we use the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

Mass of propane = 44 grams

Molar mass of propane = 44 grams

Putting values in above equation, we get:

$\text{moles of propane}=\frac{44g}{44g/mol}=1mole$

For the reaction of combustion reaction of propane, the equation follows:

$C_3H_8+5O_2\rightarrow 3CO_2+4H_2O$

By Stoichiometry of the reaction,

1 mole of propane produces 4 moles of water.

So, 1 mole of propane will produce = $\frac{1}{1}\times 4=4moles$ of water.

Now, to calculate the amount of water, we use equation 1, we get:

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Mass of water produced = 72 grams

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