Moles of Carbondioxide-CO₂ produced = 20 moles
<h3>Further explanation</h3>
The combustion of hydrocarbons with excess oxygen will produce carbon dioxide and water(CO₂+H₂O), whereas if there is not much oxygen, carbon monoxide and water(CO+H₂O) will be obtained.
The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds
Reaction (combustion of butane) :
<em>2C₄H₁₀+13O₂⇒8CO₂+10H₂O</em>
Butane reacts completely, then Butane is the limiting reactant and oxygen as the excess reactant, so the moles of Carbon dioxide are based on the butane moles as the limiting reactant.
moles of butane - C₄H₁₀ = 5 moles
From the reaction, the mol ratio of C₄H₁₀ and CO₂ : 2 : 8, so mol CO₂ :

Answer:
1. Rutherford did the scattering experiment and observed that some of the rays bounce back. He concluded that there is a mass in which positive charge is concentrated. This marks the discovery of nucleus.
2. J.J Thomson discovered electrons by conducting cathode ray experiment.
3. Dalton postulated that matter is made up of small particles caled atoms
Answer is: concentration is 1.3 ppm.
Parts-per-million (10⁻⁶) is present at one-millionth of a gram per gram of sample solution, for example mg/kg.
d(Cu) = 0.0013 g/L; mass concentration of copper.
d(H₂O) = 1.00 g/mL; density of water.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 1000 mL · 1 g/mL.
m(H₂O) = 1000 g ÷ 1000 g/kg.
m(H₂O) = 1 kg; mass of water.
m(Cu) = 0.0013 g · 1000 mg/g.
m(Cu) = 1.3 mg; mass of coppper.
concentration = 1.3 mg ÷ 1 kg.
concentration = 1.3 mg/kg.
concentration = 1.3 ppm.