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Aliun [14]
3 years ago
11

I need help with this question...​

Chemistry
2 answers:
Novosadov [1.4K]3 years ago
8 0
I think it’s ax ..............
ivanzaharov [21]3 years ago
5 0
I’m guessing the answer is AX (the first one) sorry if I am wrong tho
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A bike lost 20% of its value after the first year, its value after the first year is $1039. Calculate the original price of the
musickatia [10]

Answer:

$1246.90

Explanation:

Since the bike lost 20%% of it's value and it now currently at $$1039, we have to do 20% * $1039 to find the amount of money lost. 20%*1039=207.8. We have to add it up to find the original value so 1039+207.8=$1246.8

6 0
2 years ago
Henok is observing the reaction rate of a chemical reaction. He then adds a catalyst to the reaction.
tia_tia [17]
A catalyst will ALWAYS increase the reaction rate so C
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3 years ago
Briefly describe how the pH of a colourless solution could be measured using a universal indicator​
Firdavs [7]

Answer:

Universal indicator can show us how strongly acidic or alkaline a solution is, not just that the solution is acidic or alkaline. This is measured using the pH scale , which runs from pH 0 to pH 14.

Explanation:

~Hope this helps

4 0
3 years ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
Humans do things that can affect the
Dmitriy789 [7]

Answer:

they cause animals home's to be destroyed

Explanation:

8 0
3 years ago
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