The average speed of the family : 70 km/h
<h3>Further explanation</h3>
Given
time = 2 hour
distance = 140 km
Required
The average speed
Solution
Distance is the length traveled by an object within a certain time
Average speed = total distance/total amount of time
Can be formulated :
Avg speed = d : t
Total distance traveled : 140 km
Total time : 2 hr
Avg speed = 140 : 2 = 70 km/h
The significant figure is only 1 which is just the number 5. The zeros don't count.
1. CH4
2. Br2
3. 25 g/mol
Graham's law indicates that the rate of diffusion is inversely proportional to the square root of its molecular weight. So the lighter the gas, the more rapid the diffusion. With that in mind, let's look at your questions:
1. A flask contains four gases: CH4, O2, C2H5, and N2. When the stopper is removed, which gas will diffuse the fastest?The answer here will be the lightest of the 4 gasses. So let's look at the molar mass of each gas:
CH4 = 16.04 g/mol
O2 = 32.00 g/mol
C2H5 = 29.06
N2 = 28.01
And CH4 is the lightest and therefore the fastest.
2. Which gas effuses 2.39 times slower than nitrogen gas? O2 Cl2 Br2 <--- I2
Let's start with the square root of 28.01 which is 5.292447449.
Now multiply by 2.39 and square the result to get the molar mass of the
desired gas which is (5.29*2.39)^2 = 12.64^2 = 159.77Now let's look at the molar masses.
O2 = 32
Cl2 = 70.91
Br2 = 159.81
I2 = 253.81
And the match goes to Br2
3. What is the molecular mass of a gas that effuses three times faster than radon? 16 g/mol 25 g/mol <--- 50 g/mol 67 g/mol,The molar mass of radon is 222 g/mol. So let's get the square root, divide by
3, then square the result. So(sqrt(222)/3)^2 = (14.89966443/3)^2 = 4.966554809^2 = 24.66666667 g/mol.And of the available choices, 25 g/mol is the best match.
Answer:
EVERYTHING!!!! Okay, but really he didn't show in his model that there is different charges distributed in the atom.
Explanation:
The molarity of the HBr solution is 0,172 M.
The neutralization reaction between LiOH and HBr is the following:
HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)