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11111nata11111 [884]
3 years ago
11

The analysis of a compound containing K, P and O showed 55 % K, 15 % P and 30 % O, set up the simplest empirical formula of this

compound.
Chemistry
1 answer:
Leokris [45]3 years ago
4 0

Answer:

Empirical formula is K₃PO₄.

Explanation:

Given data:

Percentage of K = 55%

Percentage of P = 15%

Percentage of O = 30%

Empirical formula = ?

Solution:

Number of gram atoms of K = 55 / 39.098 = 1.41

Number of gram atoms of P = 15 /30.974= 0.48

Number of gram atoms of O = 30 / 15.999 = 1.88

Atomic ratio:

             K                      :          P                   :         O

           1.41/0.48            :       0.48/0.48        :       1.88/0.48

               3                     :           1                    :            4

K : P : O = 3 : 1 : 4

Empirical formula is K₃PO₄.

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<h3>Further explanation</h3>

Given

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1. CH4
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Graham's law indicates that the rate of diffusion is inversely proportional to the square root of its molecular weight. So the lighter the gas, the more rapid the diffusion. With that in mind, let's look at your questions:

1. A flask contains four gases: CH4, O2, C2H5, and N2. When the stopper is removed, which gas will diffuse the fastest?The answer here will be the lightest of the 4 gasses. So let's look at the molar mass of each gas:
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