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2 years ago

Please help Me I really need it

Chemistry

1 answer:

butalik [34]2 years ago

7 0

Can you show the question that goes with those answer pls

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Un gas ocupa 24,6 litros a 27°C y 10 moles, que presión posee. R=0.082

Anastasy [175]

Answer:

$P=10 atm$

Explanation:

Hola,

En este caso, usando la ecuación del gas ideal, podemos calcular facilmente la presión a partir de:

$PV=nRT$

Por lo que despejando para la presión obtenemos:

$P=\frac{nRT}{V}$

Así, calculamos:

$P=\frac{10mol*0.082\frac{atm*L}{mol*K}*(27+273)K}{24.6L} \\\\P=10 atm$

¡Saludos!

7 0

3 years ago

Manual says that he has reduce the amount of thermal energy in a cup of hot chocolate without lowering the temperature.How is th

ANEK [815]

Friction. It transforms other forms of energy into thermal energy

7 0

2 years ago

Heterozygous- a person having two different alleles for a gene is also called

Lisa [10]

Answer:

heterozygous.

Explanation:

A genotype consisting of two different alleles of a gene for a particular trait (Aa). Individuals who are heterozygous for a trait are referred to as heterozygotes.

3 0

2 years ago

Why do you think large differences in temperature between the wet bulb and dry bulb thermometers are possible only at higher tem

olganol [36]

Answer:

This is the temperature indicated by a moistened thermometer bulb exposed to the air flow. The evaporation is reduced when the air contains more water vapor. The wet bulb temperature is always lower than the dry bulb temperature but will be identical with 100% relative humidity.

Explanation:

7 0

2 years ago

If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did

user100 [1]

Answer:

4.5 L water we have in litres (L).

Explanation:

$Q=m\times c \times \Delta T$

where

$\Delta T$ = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0 cal/(g℃))

m is the mass of water

Plugging in the values

$\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$$

So,

Volume of water = mass/density

$\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$$

=4.5 L (Answer)

6 0

3 years ago