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vivado [14]
3 years ago
15

Please help Me I really need it

Chemistry
1 answer:
butalik [34]3 years ago
7 0
Can you show the question that goes with those answer pls
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Complete this nuclear reaction by selecting which particle would go in the
kompoz [17]

Answer:

Missing particles: ^{0}_{1}e^{+} (a positron) and an electron neutrino \nu_{\rm e}.

The nuclear equation would be:

{\rm ^{19}_{10} Ne} \to ^{0}_{1}e^{+} + {\rm ^{19}_{\phantom{1}9}F }+ \nu_{e}.

Explanation:

The mass number of a particle is the number on the top-right corner of its symbol.

The atomic number of a particle is the number on the lower-right corner of its symbol.

The nuclear reaction here resembles a beta-plus decay. The mass numbers of the two nuclei are equal. However, the atomic number of the product nucleus is lower than that of the reactant nucleus by 1.

A beta decay may either be a beta-plus decay or a beta-minus decay. In a beta-plus decay, a positively-charged positron ^{0}_{1}e^{+} and an electron neutrino \nu_e would be released. On the other hand, in a beta-minus decay, a negatively-charged electron \rm ^{0}_{1}e^{-} and an electron antineutrino \overline{\nu}_e would be released.

Electric charge needs to be conserved in nuclear reactions, including this one.

The atomic number of the \rm Ne nucleus on the left-hand side is 10, meaning that the nucleus has a charge of +10. On the other hand, the atomic number of the \rm F nucleus on the right-hand side shows that this nucleus carries a charge of only +9.

By the conservation of electric charge, the particles on the right-hand side must carry a positive charge of +1. That rules out the possibility of the combination of one negatively-charged electron \rm ^{0}_{1}e^{-} (with a charge of -1) and an electron antineutrino \overline{\nu}_e (with no electric charge at all.)

Hence, the only possibility is that the missing particle is a positron (and an electron neutrino \nu_e, which carries no electric charge.)

4 0
3 years ago
What are the resonance structures of the<br>carbonate (CO32-) ion?​
postnew [5]

Answer:

go search google so dum

Explanation:

4 0
3 years ago
How many single covalent bonds could an element with the electron
Tcecarenko [31]

Answer:

1

Explanation:

I would say 1 because that configuration has 7 valence electrons.  The goal of the atom is to gain a full octet so it just needs to gain 1 more electron to get the full octet.  To get the one electron to fill the valence shell it would only need to have 1 covalent bond.

I hope this helps.  Let me know if anything is unclear.

5 0
3 years ago
How are seasons different North &amp; South of the equator
Readme [11.4K]

Answer:

seasons experienced by the northern and southern hemisphere always differ by six months  when it is summer in the northern hemisphere, it is winter in the southern hemisphere

Explanation:

6 0
3 years ago
Read 2 more answers
A gas has an initial volume of 52.3 L at 273 Kelvin. What is its temperature when the volume reaches 145.7 L?
erastovalidia [21]

Answer:

\boxed {\boxed {\sf 761 \ K}}

Explanation:

We are asked to find the new temperature of a gas after a change in volume. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

\frac {V_1}{T_1}= \frac{V_2}{T_2}

The volume is initially 52.3 liters at a temperature of 273 Kelvin.

\frac {52.3 \ L}{273 \ K}= \frac{V_2}{T_2}

The volume reaches 145.7 liters at an unknown temperature.

\frac {52.3 \ L}{273 \ K}= \frac{145.7 \ L }{T_2}

We are solving for the new temperature, so we must isolate the variable T₂.  Cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

52.3 \ L * T_2 = 273 \ K * 145.7 \ L

Now the variable is being multiplied by 52.3 liters. The inverse of multiplication is division. Divide both sides by 52.3 L.

\frac {52.3 \ L * T_2 }{52.3 \ L}=\frac{ 273 \ K * 145.7 \ L}{52.3 \ L}

T_2=\frac{ 273 \ K * 145.7 \ L}{52.3 \ L}

The units of liters cancel.

T_2=\frac{ 273 \ K * 145.7 }{52.3 }

T_2 = 760.5372849 \ K

The original measurements have at least 3 significant figures, so our answer must have 3. For the number we found, that is the ones place. The 5 in the tenths place tells us to round the 0 up to a 1.

T_2 \approx 761 \ K

When the volume reaches 145.7 liters, the temperature is <u>761 Kelvin.</u>

8 0
3 years ago
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