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3 years ago

Referring to the experiment in which the scientists studies how long it

Chemistry

1 answer:

pshichka [43]3 years ago

4 0

Answer:

different sizes of the parachute

Explanation:

this is what is being changed throughout the experiment

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How do particles move when they are changing phases?

Arisa [49]

They speed up when they get hotter and they slow down when they get colder. I think

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3 years ago

What is the frequency of green light that has a wavelength of 5.14 x 10^-7m?

nata0808 [166]

Answer:

Frecuency = 5,83x10⁻⁷ Hz

Explanation:

The equation that connects wavelenght and frequency is given by:

λ = c/ν

λ=wavelenght (expressed in lenght´s units)

c= speed of light (3x10⁸ m/sec)

ν=frequency (expressed in units of time⁻¹ or Herzt)

In our case, λ=5,14x10⁻⁷ m , so replacing in our previous formula, this gives us the final result of ν (frequency for green light) of 5,83x10¹⁴ Hz (or Herzt)

5 0

3 years ago

Describe two advantages and two disadvantages of building your 3D model with modeling clay. (5 points)

marishachu [46]

Answer:

A model or simulation is only as good as the rules used to create it. It is very difficult to create an entirely realistic model or simulation because the rules are based on research and past events. The main disadvantage of simulations is that they aren't the real thing.

Explanation:

8 0

3 years ago

Becker did an experiment. Separately, Tracy did the exact same experiment. Becker and Tracy found they each got very different r

maxonik [38]

Answer:

I don't know

Explanation:

Maybe they shouldn't copy each other

5 0

3 years ago

Read 2 more answers

A student reacts 5.0 g of sodium with 10.0 g of chlorine and collect 5.24 g of sodium chloride. What is the percent yield of thi

Ede4ka [16]

Answer: The percent yield of this combination reaction is 41.3 %

Explanation : Given,

Mass of $Na$ = 5.0 g

Mass of $Cl_2$ = 10.0 g

Molar mass of $Na$ = 23 g/mol

Molar mass of $Cl_2$ = 71 g/mol

First we have to calculate the moles of $Na$ and $Cl_2$ .

$\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}$

$\text{Moles of }Na=\frac{5.0g}{23g/mol}=0.217mol$

and,

$\text{Moles of }Cl_2=\frac{\text{Given mass }Cl_2}{\text{Molar mass }Cl_2}$

$\text{Moles of }Cl_2=\frac{10.0g}{71g/mol}=0.141mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation will be:

$2Na+Cl_2\rightarrow 2NaCl$

From the balanced reaction we conclude that

As, 2 mole of $Na$ react with 1 mole of $Cl_2$

So, 0.217 moles of $Na$ react with $\frac{0.217}{2}=0.108$ moles of $Cl_2$

From this we conclude that, $Cl_2$ is an excess reagent because the given moles are greater than the required moles and $Na$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaCl$