There is one electron in the valence shell of every halogen. Two halogen atoms join together to form a covalent connection (sharing one electron each). Thus, inter-halogen compounds with 1+ or a 1- charge contain an even number of atoms.
An interhalogen compound is a molecule with no atoms from any other group of elements and two or more different halogen atoms (fluorine, chlorine, bromine, iodine, or astatine). The majority of interhalogen chemicals are binary (composed of only two distinct elements).
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Answer:
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Explanation:
Answer:
The final molarity of acetate anion in the solution is 0.0046 moles
Explanation:
The balanced equation is
Cu(C₂H₃O₂)₂ + Na₂CrO₄ = CuCrO₄ + 2Na(C₂H₃O₂)
Therefore one mole of Cu(C₂H₃O₂)₂ react with one mole of Na₂CrO₄ to form one mole of CuCrO₄ and two moles of Na(C₂H₃O₂)
Mass of copper (II) acetate present = 0.708 g
Volume of aqueous sodium present = 50 mL
Molarity of sodium chromate = 46.0 mM
Therefore
Number of moles of sodium chromate present = (50 mL/1000)×46/1000 = 0.0023 M
Number of moles of copper (II) acetate present = 181.63 g/mol
number of moles of copper (II) acetate present = (0.708 g/181.63 g/mol) =0.0039 moles
Therefore 0.0039 moles of Cu(C₂H₃O₂)₂ × (2 moles of Na(C₂H₃O₂))/1 Cu(C₂H₃O₂)₂) = 0.00779 moles of Na(C₂H₃O₂)
also 0.0023 moles of Na₂CrO₄ × (2 moles of Na(C₂H₃O₂))/1 Na₂CrO₄) = 0.0046 moles of Na(C₂H₃O₂)
Therefore the Na₂CrO₄ is the limiting reactant and 0.0046 moles of Na(C₂H₃O₂) or acetate anion is formed
Climax (the most exciting or plot changing event)
Answer: 0.024 M
Explanation:
According to the neutralization law,
where,
= molarity of stock solution = 0.12 M
= volume of stock solution = 20.0 ml
= molarity of diluted solution = ? M
= volume of diluted solution = 100.0 ml
Putting in the values we get:
Therefore, the concentration of the resulting solution is 0.024 M.
