Given :
Three block of same mass name A , B and C .
Sides of block A , B and C is 3.0 cm , 5.0 cm and 10.0 cm .
To Find :
Which block has the higher density .
Solution :
We know , density
is given by :
......1 )
Here , V is volume .
Now , volume V for cube is given :
.......2 )
( Here , a is the side of cube )
Now ,form equation 1 we can see if mass remains constant then density decrease with increase in volume.
Therefore , cube with minimum side will have higher density , in this case it is 3 cm block .
Hence , this is the required solution .
poste en français s’il vous plaît
2.11x10^24 Ca atoms
In order to find the amount of atoms we must use Avogadro’s number, 6.022 x 10^23
Since we have moles, 3.5 the equation would look like this
3.5 moles Ca x 6.022x10^23/1 = 2.1077 x 10^24, which we round to 2.11 x 10^24 atoms of Ca