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3 years ago

What is the mass of 4.44 moles of P2O5

Chemistry

1 answer:

adell [148]3 years ago

6 0

4 because I said so my dude djdjdndjd

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How many grams are there in 2.7 x 1021 molecules of NiNz?

Inessa05 [86]

Answer:

2.7 x 1021=2756.7

Explanation:

I don't know what NiNz is

3 0

3 years ago

Nail polish remover containing acetone was spilled in a room 7.2 m × 5.8 m × 3.9 m. Measurements indicated that 6,400 mg of acet

sergeinik [125]

Volume of room = $7.2 m \times 5.8 m \times 3.9 m$

= $162.864 m^{3}$

Now, according to conversion factor, convert 6,400 mg to micrograms

Since, 1 mg is equal to 1000 microgram.

Therefore, 6,400 mg = $6,400 \times 1000$

= 6,400,000 micrograms of acetone.

To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.

Thus,

Concentration of acetone = $\frac{6,400,000 microgram}{162.864 m^{3}}$

= 39296.5910 microgram per cubic meter or $3.92\times 10^{4} \mu g/m^{3}\simeq 4.0\times 10^{4} \mu g/m^{3}$

Hence, concentration of acetone is equal to $4.0\times 10^{4} \mu g/m^{3}$

7 0

3 years ago

Which element’s atoms have the greatest average number of neutrons?

algol [13]

Answer:

not sure but i guess it's Tellurium

6 0

3 years ago

Read 2 more answers

5. The number of atoms in 9.2 g of Na will be: A. 6.2 x 1023 atoms B. 2.408 x 1023 atoms C. 9.2 x1023 atoms D. 23 atoms E. 9.2 a

cluponka [151]

Answer:

The answer is "Option B"

Explanation:

Formula:

Na atoms= Na atoms moles \times NA

$= \frac{mass}{Na \ Molar\ mass} \times 6.022 \times 10^{23}\\\\= \frac{9.2}{23} \times 6.022 \times 10^{23}\\\\=0.2875 \times 6.022 \times 10^{23}\\\\=2.4 \times 10^{23}\ atoms \\\\$

4 0

3 years ago

The chemical equation below shows the reaction between tin (Sn) and hydrogen fluoride (HF). Sn + 2HF mc017-1.jpg SnF2 + H2 The m

Sergio [31]

Tin and Hydrofluoric Acid reacts as shown,

 Sn + 2 HF → SnF₂ + H₂

According to Equation,

40.02 g (2 Moles) HF Required = 1 Mole of Sn for complete Reaction

So,
40 g of HF will require = X Moles of Sn

Solving for X,
X = (40 g × 1 Mole) ÷ 40.02 g

X = 0.999 Moles ≈ 1 Mole
Result:
40 g of HF requires 1 Mole of Tin (Sn) for complete Reaction to produce SnF₂ and H₂.

7 0

3 years ago

Read 2 more answers