Answer:
The mass of silicon in kilograms in Earth's crust is
.
Explanation:
Mass of Earth =
(1 ton= 2000 lb)
(1 lb =453.6 g)
1 ton = 2000 × 453.6 g =907,200 g
Mass of Earth =
Percentage of earth crust = 0.50%
Mass of earth crust = M


Percentage of the silicon in Earth's crust = 27.2 %
Mass of silicon in in Earth's crust = m



1000 g = 1 kg
The mass of silicon in kilograms in Earth's crust is
.
The intermolecular force that attracts two nonpolar molecules is London dispersion forces, which are also called induced dipole-induced
Question:
Sulfuric acid was once produced through the reaction of sulfur trioxide with water. Sulfur trioxide can form through the reaction of sulfur dioxide and oxygen gas. When nitrogen monoxide gas is added to the system, the reaction speeds up significantly because it proceeds through the following steps:
equations
Identify the catalyst in this reaction, explain how you know it is the catalyst, and describe how it increases the rate of the reaction.
Answer:
NO
It is present but not consumed
NO Lowers the activation energy of the reaction
Explanation:
A catalyst is a substance that is present in a chemical reaction and enables the reaction to occur at a faster rte but does not take part n the reaction
Therefore, whereby NO is not consumed, it is the catalyst
It functions by lowering the activation energy
<u>Answer:</u> The molar mass of the insulin is 6087.2 g/mol
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

Or,

where,
= osmotic pressure of the solution = 15.5 mmHg
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of solute (insulin) = 33 mg = 0.033 g (Conversion factor: 1 g = 1000 mg)
Volume of solution = 6.5 mL
R = Gas constant = 
T = temperature of the solution = ![25^oC=[273+25]=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5D%3D298K)
Putting values in above equation, we get:

Hence, the molar mass of the insulin is 6087.2 g/mol
Answer:
d = 0.793 g/L
Explanation:
Given data:
Density of fluorine gas = ?
Pressure of gas = 0.554 atm
Temperature of gas = 50 °C (50+273.15K = 323.15 K)
Solution:
Formula:
PM = dRT
M = molar mass of gas
P = pressure
R = general gas constant
T = temperature
d = PM/RT
d = 0.554 atm × 37.99 g/mol / 0.0821 atm.L /mol.K × 323.15 K
d = 21.05 atm.g/mol/26.53 atm.L /mol
d = 0.793 g/L