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3 years ago

Find the "density" of a copper sample whose mass is 134.4 grams and whose volume is 15.0mL

Chemistry

1 answer:

Arisa [49]3 years ago

6 0

Answer: 8.96 g/mL

Work Shown:

density = mass/volume

density = (134.4 grams)/(15.0 mL)

density = (134.4/15.0) g/mL

density = 8.96 g/mL

This result is to 3 sig figs which is the smaller sig fig count when comparing the original values 134.4 and 15.0; so this means we don't have to do any rounding.

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When combining acids and water, water should always be added to the acid. True or False?

scoundrel [369]

Answer:

False

Explanation:

Always add acid to the water, it dilutes the acid the other way around.

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3 years ago

A mixture in which particles are not evenly distributed and particles keep their unique properties.

lina2011 [118]

<h2>Answer : Option D) Heterogeneous mixture</h2><h3>Explanation : </h3>

A mixture in which particles are not evenly distributed and particles keep their unique properties are called as heterogeneous mixture.

Usually, in heterogeneous mixture the substances are not evenly distributed and they can be easily separated through any physical methods. Also the components retains their original/unique properties in the mixture. It usually contains various particles from different substances that are not uniformly distributed throughout the mixture.

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3 years ago

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In your own words list the rules for naming hydrocarbons and substituted hydrocarbons. Be detailed in listing all rules includin

Irina18 [472]

Answer :

The basic rules for naming of hydrocarbons are :

First select the longest possible carbon chain.

The longest possible carbon chain should include the carbons of double or triple bonds.

The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne.

The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.

The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.

If two or more similar alkyl groups are present in a compound, the prefixes di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.

8 0

3 years ago

a 5L container contains 3 moles of helium and 4 moles of hydrogen at a pressure of 9 atms maintaining a constant T and additiona

Stells [14]

Answer:

7.71 atm

Explanation:

Given the following data:

$V = 5 L$

$n_{He} = 3 mol$

$n_{H_2} = 4 mol$

$p_1 = 9 atm$

$T = const$

According to the ideal gas law, we know that the product between pressure and volume of a gas is equal to the product between moles, the ideal gas law constant and the absolute temperature:

$pV = nRT$

Since the temperature and the ideal gas constant are constants, as well as the fixed container volume of 5 L, we may rearrange the equation as:

$\frac{p}{n}=\frac{RT}{V}=const$

This means for two conditions, we'd obtain:

$\frac{p_1}{n_1}=\frac{p_2}{n_2}$

Given:

$p_1 = 9 atm$

$n_1 = n_{initial total} = n_{He} + n_{H_2} = 3 mol + 4 mol = 7 mol$

$n_2 = n_{final total} = n_{He} + n_{H_2} = 3 mol + 4 mol + 2 mol = 9 mol$

Solve for the final pressure:

$p_2 = p_1\cdot \frac{n_2}{n_1}$

Now, according to the Dalton's law of partial pressures, the partial pressure is equal to the total pressure multiplied by the mole fraction of a component:

$p_{H_2}=\chi_{H_2}p_2$