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svlad2 [7]
3 years ago
12

The pKa of benzoic acid is 4.2. At pH 2.0, it will exist mainly as and occupy the layer. At pH 4.2, it will exist mainly as and

occupy the:_______________
Chemistry
1 answer:
kogti [31]3 years ago
7 0

Answer:

pH 2.0; benzoic acid, layer: organic

pH 4.2; benzoic acid and benzoate anion, water layer

Explanation:

pH2.0: a lower PH than the pKa it becomes protonated and remains in the organic layer as benzoic acid, organic layer:

pH 4.2: at pH of 4.2 moves to the benzoic acid and benzoate anion, layer: water and organic

pH 12.0: at pH above the pKa it is more soluble in water hence benzoate anion, layer: water

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0.0381g/mL will be concentration of this solution

The ratio of a solute—a substance that dissolves—to a solvent—a substance that does not dissolve—determines the concentration of a solution in chemistry. C = m/V, where C is the concentration, m is the mass of the solute dissolved, and V is the overall volume of the solution, is the accepted formula.

How to reach the solution?

First find for the density of NaOh which is 2.13 g/cm3

3.88 ÷ 2.13 = 1.82mL

100mL + 1.82mL = 101.82mL

3.88 ÷ 101.82mL = 0.0381g/mL

More about NaOh:

The extremely adaptable chemical sodium hydroxide (NaOH), sometimes referred to as caustic soda or lye, is employed in a range of manufacturing processes. A byproduct of the manufacturing of chlorine is sodium hydroxide. Numerous items that are used on a daily basis, including paper, metal, drain and oven cleansers for industry, soap, and detergents, are made with sodium hydroxide.

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2 years ago
A period of the periodic table ends with the highest energy level of an element's ators<br> having?"
andrey2020 [161]

Answer:

the last period. i think has the largest energy level

Explanation:

7 0
3 years ago
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
lesya692 [45]
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Answer:

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Explanation:

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we can say that

n2 = n1 \times \frac{V2}{V1}

where,

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V2 = 12.0 L

And, the V1 = 48.0 L

Now placing these values to the above formula

So, the moles of gas in n2 left is

= 1.80 \times \frac{12.0\ L}{48.0\ L}

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