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sammy [17]
3 years ago
15

How many moles of n are in 0.195 g of n2o?

Chemistry
2 answers:
Blababa [14]3 years ago
8 0

Explanation:

As molar mass of N_{2}O is 44.013 g/mol and it is given that its mass is 0.195 g.  

Therefore, calculate its number of moles as follows.

              No. of moles = \frac{mass}{\text{molar mass}}

                                    = \frac{0.195 g}{44.013 g/mol}

                                    = 0.0044 mol

Here, in 1 mole of N_{2}O there is 2 mole of N. Thus, moles of N present in it is calculated as follows.

                             2 \times 0.0044 mol

                                 = 0.0088 mol

Thus, we can conclude that in 0.195 g of N_{2}O there are 0.0088 mol of N.

ivann1987 [24]3 years ago
4 0
0.195g N2O x 2moles of N / 28g of N = 5.46 moles of N



2X14= 28g.
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How many atoms are there in 8.88 g Si?
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Answer:

\boxed {\boxed {\sf 1.90 \times 10^{23} \ atoms \ Si}}

Explanation:

We are asked to find how many atoms are in 8.88 grams of silicon.

<h3>1. Grams to Moles </h3>

First, we convert grams to moles. We use the molar mass or the mass of 1 mole of a substance. These values are found on the Periodic Table as they are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.

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We will convert using dimensional analysis. Set up a conversion factor with the molar mass.

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We are converting 8.88 grams of silicon to moles, so we multiply by this value.

8.88 \ g \ Si *\frac { 28.085 \ g \  Si}{1 \ mol \ Si}

Flip the fraction so the units of grams of silicon cancel.

8.88 \ g \ Si *\frac{1 \ mol \ Si} { 28.085 \ g \  Si}

8.88  *\frac{1 \ mol \ Si} { 28.085 }

\frac {8.88} { 28.085 } \ mol \ Si

0.316183015845 \ mol \ Si

<h3>2. Moles to Atoms </h3>

Next, we convert moles to atoms. We use Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of silicon.

Set up another conversion factor.

\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}

Multiply by the number of moles we calculated.

0.316183015845\ mol \ Si *\frac {6.022 \times 10^{23} \ atoms \ Si}{1 \ mol \ Si}

The units of moles of silicon cancel.

0.316183015845 * \frac {6.022 \times 10^{23} \ atoms \ Si}{1}

0.316183015845 * {{6.022 \times 10^{23} \ atoms \ Si}

1.90405412 \times 10^{23} \ atoms \ Si

<h3>3. Significant Figures</h3>

The original measurement of 8.88 grams has 3 significant figures, so our answer must have the same.

For the number we calculated, that is the hundredth place. The 4 in the thousandth place tells us to leave the 0 in the hundredth place.

1.90 \times 10^{23} \ atoms \ Si

<u>8.88 grams of silicon contains 1.90 ×10²³ atoms of silicon.</u>

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C) Glucose    covalent     molecules                   0.5          0.5 × 1 × 1 = 0.5

D) Glucose    covalent     molecules                   1.0           1.0 × 1  × 1 = 1

Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.

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