Answer: The electronic configuration of nitrogen is 1s2 2s2 2p3. Thus nitrogen has a half-filled p orbital, which is comparatively more stable. Thus the p orbital is the outermost orbital. To achieve a stable gas configuration, nitrogen needs to have a fulfilled p orbital.
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Answer:
2 mol of SO3 produces 1 mol O2
3 mol SO3 produces 3/2 mol of O2
so O2 produced = 1.5(32) =48 gm
Explanation:
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1) Chemical reaction
CH3 CH2 OH + O2 ---> CH3COOH + H2O
It is balanced
2) Molar ratios
1 mol CH3 CH2OH : 1 mol O2 : 1 mol CH3COOH : 1 mol H2O
3) Conversion of 7.6 grams of ethanol to moles
Molar mass of CH3CH2OH = 2 * 12g/mol + 6 * 1 g/mol + 16 g/mol = 46 g/mol
moles = mass / molar mass = 7.6 g / 46g/mol = 0.165 mol
4) Use of proportions with the molar ratios:
1mol CH3CH2OH / 1mol O2 = 0.165 mol CH3CH2OH / x => x = 0.165 mol CH3CH2OH.
5) Conversion of 0.165 mol O2 to grams
mass in grams = number of moles * molar mass = 0.165 mol * (2 * 16g/mol)
mass = 5.28 g ≈ 5.3 g
Answer: 5.3 g