How many moles of n are in 0.195 g of n2o?
2 answers:
Explanation:
As molar mass of is 44.013 g/mol and it is given that its mass is 0.195 g.
Therefore, calculate its number of moles as follows.
No. of moles =
=
= 0.0044 mol
Here, in 1 mole of there is 2 mole of N. Thus, moles of N present in it is calculated as follows.
= 0.0088 mol
Thus, we can conclude that in 0.195 g of there are 0.0088 mol of N.
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The termination step of the free-radical chlorination of methane is the most stable one among all three steps.
The free-radical substitution reaction between chlorine and methane features three major steps:
Initiation, during which chlorine molecules undergo homolytic fission to produce chlorine free radicals. Ultraviolet radiations are typically applied to supply the energy required for breaking the chlorine-chlorine single bonds. The initiation step is thus <em>endothermic</em>.
Propagation, a process in which chlorine free radicals react with methane molecules and remove a hydrogen atom from the alkane to produce hydrogen chloride and an alkyl radical e.g., . The carbon-containing free radical would react with chlorine molecules to produce chloromethane and yet another chlorine free radical. This process can well repeat itself to chlorinate a significant number of methane molecules.
Termination. Free radicals combine to produce molecules. For example, two chlorine free radicals would combine to produce a chlorine molecule, whereas two alkyl free radicals would combine to produce an alkane with two-carbon atoms in its backbone.
Chemical processes that increase the stability of a substance reduces its chemical potential energy. Energy conserves, thus such processes would also release energy equal to the potential energy lost in quantity. Free radicals are unstable and- as seen in the propagation step- compete readily with neutral molecules for their electrons. The propagation step keeps the number of free radicals constant and is therefore more exothermic than the initiation step. The termination step reduces the number of free radicals, increase the stability of the system by the greatest extent, and is therefore the most exothermic step among the three.
Answer : The volume given to the patient should be, 85.5 mL
Explanation :
As we are given that the suspension contains 10g/15mL.
Now we have to determine the volume should be given to the patient.
As, 10 grams of lactulose syrup needed 15 mL volume of solution
So, 57 grams of lactulose syrup needed volume of solution
Thus, the volume given to the patient should be, 85.5 mL