what radius (mm) must a steel (iron) ball bearing have if it is to have a mass of 3.25g? density of iron = 7.86g/cm3 V=4/3 pie r
1 answer:
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Answer : The temperature of liquid is, 369.9 K
Explanation :
The Clausius- Clapeyron equation is :
where,
= vapor pressure of liquid at 373 K = 681 torr
= vapor pressure of liquid at normal boiling point = 760 torr
= temperature of liquid = ?
= normal boiling point of liquid = 373 K
= heat of vaporization = 40.7 kJ/mole = 40700 J/mole
R = universal constant = 8.314 J/K.mole
Now put all the given values in the above formula, we get:
Hence, the temperature of liquid is, 369.9 K
Answer:
The ionization equation is
⇄
(1)
Explanation:
The ionization equation is
⇄
(1)
As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.
The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,
The pKa is
The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.
In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.
If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1) moves to the left neutralizing the excess proton concentration.
<u>Answer:</u> The heat required will be 58.604 kJ.
<u>Explanation: </u>
To calculate the amount of heat required, we use the formula:
Q= heat gained or absorbed = ? J
m = mass of the substance = 100 g
c = heat capacity of water = 4.186 J/g ° C
Putting values in above equation, we get:
Q = 58604 Joules = 58.604 kJ (Conversion factor: 1 kJ = 1000J)
Thus, heat released by 100 grams of ice is 58.604kJ.