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Goryan [66]
2 years ago
12

what radius (mm) must a steel (iron) ball bearing have if it is to have a mass of 3.25g? density of iron = 7.86g/cm3 V=4/3 pie r

3
Chemistry
1 answer:
nydimaria [60]2 years ago
3 0

Answer:

Radius of the steel ball is 4.6mm

Explanation:

Hello,

To find the radius of the steel, we'll have to calculate it from it's volume which can be gotten from the density of the material.

Data;

Mass = 3.25g

Density = 7.86g/cm³

Density = mass / volume

Volume = mass / density

Volume = 3.25 / 7.86

Volume = 0.413cm³

Volume of a steel = 4/3πr³

0.413 = 4/3 × π × r³

0.413 = 1.33 × 3.14 × r³

0.413 = 4.1762r³

r³ = 0.413 / 4.1762

r³ = 0.099

Take the cube root of both sides

r = 3√(0.099)

r = 0.46cm

From metrics table

1cm = 10mm

0.46cm = x mm

x = (0.46 × 10)

x = 4.6mm

The radius of the steel ball is 4.6mm

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Answer:

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Explanation:

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In the saturated compounds, the molecules are tightly packed side by side with minimal steric hindrance and maximal van der Waals forces of attraction between molecules. However, in unsaturated fatty acids, the cis double bond introduces a bend or kink in the molecules which then interferes with the tight packing of the molecules and reducing interaction between molecules. Therefore, less energy is required to cause a disorder in the arrangement of unsaturated fatty acids, leading to a lowering of melting point.  

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Explanation:

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Therefore, we have;

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