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sweet [91]
3 years ago
5

4 NH3 +5 02 +4NO + 6H2O When 70.25 grams of NH3 react, how many moles of H20 are produced?

Chemistry
1 answer:
romanna [79]3 years ago
5 0

Answer:

6.19 mol H₂O

Explanation:

  • 4 NH₃ + 5O₂ → 4NO + 6H₂O

First, we<u> convert 70.25 grams of NH₃ into moles</u>, using its<em> molar mass</em>:

  • 70.25 g ÷ 17 g/mol = 4.13 mol NH₃

Then we <u>convert 4.13 moles of NH₃ into moles of H₂O</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 4.13 mol NH₃ * \frac{6molH_2O}{4molNH_3} = 6.19 mol H₂O
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The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the following Charle's law equation:

V1/T1 = V2/T2

Where;

  • T1 = initial temperature
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9/325 = V2/450

325V2 = 4050

V2 = 4050/325

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Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

Learn more about volume at: brainly.com/question/2817451

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