I am sorry if it didn't helped
answers;
Calculate the buoyant force of a piece of cork of 8cm3 that floats in water. Density of cork is 207kg/m3. ?
I need the mass, in order to get the volume to apply t to the Buoyancy formula of: B=(W)object=(m)object(g)
Explanation:
From Archimedes Principle, any object partially or totally submerged in a fluid is buoyed upwards with a force equal to the weight of the displaced fluid.
∴
B
=
ρ
f
l
V
f
l
g
=
1000
k
g
/
m
3
×
8
×
10
−
6
m
3
×
9
,
8
m
/
s
2
=
0
,
0784
N
(assuming the density of water is at standard temperature and pressure, and that the cork is totally submerged as it floats in the water
it's not the answer of your question ⁉️ but it is similar ........
Answer:
8977.7 kg/m^3
Explanation:
Volume of water displaced = 55 cm^3 = 55 x 10^-6 m^3
Reading of balance when block is immersed in water = 4.3 N
According to the Archimedes principle, when a body is immersed n a liquid partly or wholly, then there is a loss in the weight of body which is called upthrust or buoyant force. this buoyant force is equal to the weight of liquid displaced by the body.
Buoyant force = weight of the water displaced by the block
Buoyant force = Volume of water displaced x density of water x g
= 55 x 10^-6 x 1000 x .8 = 0.539 N
True weight of the body = Weight of body in water + buoyant force
m g = 4.3 + 0.539 = 4.839
m = 0.4937 kg
Density of block = mass of block / volume of block
= 
Density of block = 8977.7 kg/m^3
In a stronger gravitational field a given mass will have a larger weight.
Unless if all forces cancel each other out , the object will no longer be in equilibrium
Use the formula M=D×V:
M=10 g/cm³ * 5 cm³ = 50 g
which is more than 40 grams, so the container cannot hold the chain.
