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Alexandra [31]
4 years ago
9

Earth’s largest ecosystems, biomes, are defined primarily by:

Physics
1 answer:
Darina [25.2K]4 years ago
5 0

Answer: e. All of the above.

Explanation:

Rainfall, temperature, seasonal variability are the important factors which determines the type of vegetation will grow in a biome, the type of animals will adapt and survive. Also these factors also determine the fact that type of landforms will form over a region. These factors are necessary for the development of the biodiversity. A biodiversity can be define as the variability and variety of life forms that can be found in the ecosystem or biome.      

You might be interested in
Why do disk stars bob up and down as they orbit the galaxy?
Pie

Answer:

When the stars get a little bit farther from the disk, the other stars that are still in the disk will pull them toward it as a consequence of the gravity between them.

     

Explanation:

Galaxies have different structures due to parameters as the orbit of the stars around the center of the galaxy or the metallicity¹ of the stars (which serves to find the age of the stars). For example, in the case of the Milky Way, it has:

       

The Halo

The Bulge

The Thick Disk

The Thin Disk

The Halo has old stars with low metallicities and random orbits, while the bulge has stars with the same random motions like the one in the Halo.

The Thick Disk has stars with orbits oriented in the same direction but with  metallicities a little bit higher than the one from the Halo but lower than the stars in the Thin Disk.

The stars that are in the thin disk have orbits oriented in the same direction and are the ones with the higher metallicity levels, which means that they are the most younger in the galaxy.

In general the stars in the disk of the galaxy (thick disk and thin disk) goes up and down as they orbit the center of the galaxy, <u>the reason for this is that when they get a little bit farther from the disk, the stars that are still in the disk pull them back toward it as a consequence of the gravity between them. </u>

Remember the equation of the Universal gravitation law:

F = G\frac{m1.m2}{R^{2}}  (1)

Where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of two objects and R is the distance between them.

       

Notice how equation 1 expresses that the force of gravity is inversely proportional to the square of the distance between the two objects, which means that the force of gravity will decrease as the square of the distance increase.

                   

Key terms:

¹Metallicity: the abundance of heavier elements against the presence of Helium or Hydrogen.

7 0
3 years ago
A mass suspended from a spring is oscillating up and down as indicated. Consider the following possibilities. A At some point du
dangina [55]

A mass suspended from a spring is oscillating up and down, (as stated but not indicated).

A). At some point during the oscillation the mass has zero velocity but its acceleration is non-zero (can be either positive or negative).  <em>Yes. </em> This statement is true at the top and bottom ends of the motion.

B). At some point during the oscillation the mass has zero velocity and zero acceleration.  No.  If the mass is bouncing, this is never true.  It only happens if the mass is hanging motionless on the spring.

C). At some point during the oscillation the mass has non-zero velocity (can be either positive or negative) but has zero acceleration.  <em>Yes.</em>  This is true as the bouncing mass passes through the "zero point" ... the point where the upward force of the stretched spring is equal to the weight of the mass.  At that instant, the vertical forces on the mass are balanced, and the net vertical force is zero ... so there's no acceleration at that instant, because (as Newton informed us), A = F/m .  

D). At all points during the oscillation the mass has non-zero velocity and has nonzero acceleration (either can be positive or negative).  No.  This can only happen if the mass is hanging lifeless from the spring.  If it's bouncing, then It has zero velocity at the top and bottom extremes ... where acceleration is maximum ... and maximum velocity at the center of the swing ... where acceleration is zero.  

7 0
3 years ago
calculate the deceleration of a bullet initially travelling at 360 m/s, if it is brought to rest after travelling 8.5 cm into a
sp2606 [1]

The de - acceleration of bullet from 360 m/s after it struck the tree trunk and was brought to rest is -152.54 x 10⁴ m/s².

<h3>What is Acceleration in Kinematics?</h3>

Acceleration is defined as the rate of change of velocity with respect to time. Mathematically -

<h3>a = Δv/Δt</h3>

Given is a bullet initially travelling at 360 m/s struck into a tree trunk 8.5 cm inside and comes to rest. From this, we can write

initial velocity [u] = 360 m/s

final velocity [v] = 0 m/s

distance travelled [d] = 8.5 cm = 0.085 m

The time span after which bullet comes to rest will be -

Δt = d/u

Δt = 0.085/360 = 2.36 x 10 ⁻⁴ seconds

a = Δv/Δt

Δv = 0 - 360 = - 360 m/s

a = (v - u)/Δt

a = - 360/(2.36 x 10 ⁻⁴)

a = - 152.54 x 10⁴ m/s²

Therefore, the de - acceleration of bullet from 360 m/s after it struck the tree trunk and was brought to rest is -152.54 x 10⁴ m/s².

To solve more questions on Kinematics, visit the link below-

brainly.com/question/14413005

#SPJ1

8 0
1 year ago
. Which is the transfer of energy as waves moving through space?
Solnce55 [7]

Answer:

Radiation is the answer to your question

6 0
4 years ago
What value is closest to the mass of the atom?....
Sveta_85 [38]
The answer would be 6amu
6 0
3 years ago
Read 2 more answers
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