Answer:
You dont need BRAINLY there is an app called slader where you scan the textbook barcode and it shows you the answers for the question in the textbook.
Explanation:
Answer:
a)143.8 decays/minute
b)0.41 decays/minute
Explanation:
From;
0.693/t1/2 = 2.303/t log (Ao/A)
Where;
t1/2=half-life of C-14= 5670 years
t= time taken to decay
Ao= activity of a living sample
A= activity of the sample under study
a)
0.693/5670 = 2.303/1000 log(162.5/A)
1.22×10^-4 = 2.303×10^-3 log(162.5/A)
1.22×10^-4/2.303×10^-3 = log(162.5/A)
0.53 × 10^-1 = log(162.5/A)
5.3 × 10^-2 = log(162.5/A)
162.5/A = Antilog (5.3 × 10^-2 )
A= 162.5/1.13
A= 143.8 decays/minute
b)
0.693/5670 = 2.303/50000 log(162.5/A)
1.22×10^-4 = 4.61×10^-5 log(162.5/A)
1.22×10^-4/4.61×10^-5 = log(162.5/A)
0.26 × 10^1 = log(162.5/A)
2.6= log(162.5/A)
162.5/A = Antilog (2.6 )
A= 162.5/398.1
A= 0.41 decays/minute
<u>Answer:</u>
15.97 N force is tending to pull Rover forward
<u>Explanation:</u>
The woman pulls on the leash with a force of 20.0 N at an angle of 37° above the horizontal. The arrangement is shown in the given figure,
We nee to find the pulling force P. The 20.0 N force has two components, 20.0 cos 37 in horizontal direction and 20.0 sin 37 in vertical direction.
The horizontal component is equal to pulling force P, which will pull Rover forward/
So, P = 20.0 cos 37 = 15.97 N
15.97 N force is tending to pull Rover forward.
Electromagnetic waves ARE radiation.
A wave always carries energy.
Answer:
<u>59637.2 N</u> force is required to lift the plane upward.
Explanation:
Mass of the aeroplane (m) = 5320 kg
Acceleration of the plane upward at a rate (a) = 1.40 m/s
"Newton's second law of motion", F - R = ma, where, "force" (F) acting on an object, (R) "resistive force", "mass" (m) of an object and "acceleration" (a).
Force = Resistive force + (mass × acceleration)
Resistive force = mass of an object × acceleration due to gravity. ( we know that acceleration due to gravity is 
Resistive force = 5320 × 9.81
Resistive force = 52189.2 N
Force = 52189.2 + (5320kg × 1.40 m/s)
Force = 59637.2 N
At takeoff, <u>59637.2 N</u> force is necessary to accelerate the plane upward at a rate of 1.40 m/s
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