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yuradex [85]
4 years ago
6

Usually the hull of a ship contains a large volume of air. Why?

Physics
1 answer:
Anvisha [2.4K]4 years ago
6 0
The air helps the ships move faster and use less fuel to move <span />
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It requires 2,500 joules to raise a certain amount of water (c = 4.186 J/g C) from 20 C to 60 C
Ksivusya [100]

The mass of the water is 14.9 g

Explanation:

When a certain amount of a susbtance is heated, the temperature of the substance increases according to the equation

Q=mC_s \Delta T

where

Q is the amount of energy supplied to the substance

m is the mass of the substance

C_s is its specific heat capacity

\Delta T is the change in temperature

In this problem, we have:

Q = 2500 J of energy supplied to the water

C_s = 4.186 J/gC is the specific heat capacity of water

\Delta T=60 C - 20 C = 40^{\circ}C is the change in temperature of the water

Therefore we can solve for m to find the mass of the water:

m=\frac{Q}{C_s \Delta T}=\frac{2500}{(4.186)(40)}=14.9 g

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

7 0
3 years ago
A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to
aksik [14]

Answer:

The answer is below

Explanation:

a) The vertical displacement = Δy = 21.5 m - 1.5 m = 20 m

The horizontal displacement = Δx = 69 m wide

Using the formula:

\Delta y = u_yt+ \frac{1}{2}a_yt^2\\ \\u_y=initial\ velocity\ of \ car\ in\ y\ direction = 0,a_y=g=acceleration\ due\ to\ gravity\\=10m/s^2\\\\\Delta y =  \frac{1}{2}a_yt^2\\\\\Delta y=\frac{1}{2}a_yt^2\\\\t=\sqrt{\frac{2\Delta y}{a_y} }=\sqrt{\frac{2*20}{10} }  =2\ m/s

Also:

\Delta x = u_xt+ \frac{1}{2}a_xt^2\\ \\u_x=initial\ velocity\ of \ car\ in\ x\ direction = 0,a_x=acceleration=0\\\\\Delta x =  u_xt\\\\u_x=\frac{\Delta x}{t}=\frac{69}{2} =34.5\ m/s

b)The car is moving at a constant speed in the horizontal direction, hence the initial velocity = final velocity

v_x=u_x=34.5\ m/s\\\\v_y=u_y+a_yt\\\\v_y=0+gt\\\\v_y=10(2)=20\ m/s\\\\v=\sqrt{v_x^2+v_y^2}=\sqrt{34.5^2+20^2}=39.9\ m/s\\ v=39.9\ m/s

4 0
4 years ago
This person does work to stretch the rubber band. When will the potential energy be the greatest?
antiseptic1488 [7]

the rubber band will be at its greatest when its fully stretched out

7 0
3 years ago
As the number of resistors in a parallel circuit is increased, what happens to the
aleksandr82 [10.1K]

Answer:

resistance- decreases current-increases

8 0
3 years ago
A 2.0kg mass is attached to a horizontal spring having a spring constant of 0.05Nm.
Alex Ar [27]

Good.  You can do some very interesting experiments with that equipment.

3 0
3 years ago
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