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yuradex [85]
3 years ago
6

Usually the hull of a ship contains a large volume of air. Why?

Physics
1 answer:
Anvisha [2.4K]3 years ago
6 0
The air helps the ships move faster and use less fuel to move <span />
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Which characteristic of life best describes the process of photosynthesis?
hoa [83]
Using energy.

Please vote my answer! Branliest!
7 0
3 years ago
Read 2 more answers
4 NaF + Br2 + Al(H3Li)2 --&gt;
Agata [3.3K]

Answer:

Molecules are substances that contain two or more elements, if these elements are different, then the substance is also a compound.

However, considering only the definition of a molecule, it is evident that both CH4 and NaF are molecules as they contain more than one element.

Explanation:

hope this helps!!

5 0
3 years ago
A. The cart will move to the left
zzz [600]

Answer:

A. The cart will move to the left

Explanation:

Right has more force acting on the cart than the left

4 0
2 years ago
A 50-cm-long spring is suspended from the ceiling. A 270 g mass is connected to the end and held at rest with the spring unstret
AveGali [126]

Answer:

k = 22.05 N/m

Explanation:

The potential energy of the mass is converted into potential energy of the spring.

Given:

mass m = 0.27 kg

gravitational constant g = 9.8 m/s²

distance falling/ stretching of spring h = 0.24 m

U_{gravity} = U_{spring}\\ mgh = \frac{1}{2} kh^{2}

Solving for k:

k = 2mg\frac{1}{h}

5 0
3 years ago
May
GalinKa [24]

Answer:

a)  t = 0.90 s, b)  t = 0.815 s, c)  t = 0.90 s, d)  x = 3.6 m, e)  t = 0.639 s

Explanation:

all these exercises are about kinematics

a) The body is released from rest,  

           y = y₀ + v₀ t - ½ g t²

in this case when reaching the ground y = 0 and its initial velocity is vo = 0

           0 = y₀ + 0 - ½ g t²

           t² = 2 y₀ / g

           t² = 2 4 /9.81

           t² = 0.815

            t = √0.815

           t = 0.90 s

b) It is thrown upwards at v₀ = 4 m / s

         y = y₀ + v₀ t - ½ g t²

in this case the initial and final height is the same

        y = y₀ = 0

        0 = v₀ t -1/2 g t²

        t = 2 v₀ / g

        t = 2 4 /9.81

        t = 0.815 s

c) the ball is at y₀ = 4 m and its initial velocity is horizontal v₀ = 4 m / s

        y = y₀ + v_{oy} t - ½ g t²

        0 = y₀ + 0 - ½ g t²

        t² = 2 i / g

        t² = 2 4 / 9.81

        t² = 0.815

        t = 0.90 s

d) the horizontal distance traveled is

        x = v₀ₓ t

        x = 4 0.90

        x = 3.6 m

e) We can calculate the time to fall from I = 2 m

        y = y₀ + v_{oy} t - ½ g t²

        0 = y₀ + 0 - ½ g t²

        t² = 2 y₀i / g

        t² = 2 2 /9.81

        t² = 0.4077

        t = 0.639 s

Therefore, when making measurements, you should find readings around this value.

8 0
3 years ago
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