The answer is B. Decreasing the cylinder volume decreases the amount of space the gas has to occupy there for increasing pressure
Answer:
There are 0,89 moles of nitrous oxide gas in the balloon.
Explanation:
We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:
PV= nRT ---> n= PV/RT
n= 1,09 atm x 20,0 L /0.082 l atm / K mol x 298 K
<em>n= 0,89212637 mol</em>
Answer:
B?
Explanation:
In the example, the amount of hydrogen is 202,650 x 0.025 / 293.15 x 8.314472 = 2.078 moles. Use the mass of the hydrogen gas to calculate the gas moles directly; divide the hydrogen weight by its molar mass of 2 g/mole. For example, 250 grams (g) of the hydrogen gas corresponds to 250 g / 2 g/mole = 125 moles.
Good idea!maybe I should try that
