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Ahat [919]
3 years ago
13

1. Scientists are concerned about the global temperature rise, the increase in CO2 in our atmosphere, the melting glaciers and o

ther impacts of climate change and our over use of fossil fuels. Using your previous learning on climate change (term 1 and 2) and this new information on how climate change is delaying an ice age, what is your opinion on climate change?
Chemistry
1 answer:
lana [24]3 years ago
5 0

Answer:

Climate change is bad and ok in both ways , climate change makes places hotter and hotter and can be the reason on many things that have took place and with this there is also a good side on climate change ,that is that it is delaying an ice age so i do think that it is not as bad as it is commercialized to be.

Explanation:

Thats my opinion

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When using water displament to find the volume of an irregular shaped object we use the unit...
Gekata [30.6K]
Yeah it would develop fire
5 0
2 years ago
There is a structure of CH3CH2CHCHCH2CH3, with a –CH2CH3 group attached to the third and fourth carbons.
NARA [144]

Explanation:

2,3-diethyl hexane

At first we select a long chain.

Then, we number that chain from that side where substituent position is closer.

Then, we write it's IUPAC name

Position of substituent + substituent name + chain name + suffix

Here,

2,3 + -diethyl + hex + -ane

= 2,3-diethyl hexane

7 0
2 years ago
Covalent bonds can occur where atoms share one or more pairs of electrons. Which of the following would form a double covalent b
mojhsa [17]

Answer:

The answer to your question is: CO2

Explanation:

The information given is correct, Covalent bonds occur when atoms share one or more pairs of electrons, but also, covalent bonds occur with nonmetals, then,

a.NaCl     This elements form an ionic bond, so this option is incorrect.

b.Cl2      Here there are two non metals  but the form one single covalent bond, so this option is incorrect.

c.CO2  Carbon dioxide forms 2 double covalent bonds.

d.NH3 ammonium only forms single covalent bonds

6 0
3 years ago
In a single displacement reaction between Sodium Phosphate and Barium, how much of each product (in grams) will be formed from 1
mixer [17]

Answer:

14.6 g of barium phosphate

3.35 g of sodium metal

Explanation:

2Na3PO4(aq) + 3Ba(s) -------> Ba3(PO4)2(aq) + 6Na(s)

The first step in any such reaction is to but down the balanced reaction equation according to the stoichiometry of the reaction.

The two products formed are barium phosphate and sodium metal.

Number of moles of barium corresponding to 10.0g of barium = mass of barium/ molar mass of barium

Molar mass of barium = 137.327 g

Number of moles of barium = 10/137.327

Number of moles of barium = 0.0728 moles

For barium phosphate;

3 moles of barium yields 1 mole of barium phosphate

0.0728 moles yields 0.0728 moles × 1/3 = 0.0243 moles of barium phosphate

Molar mass of barium phosphate = 601.93 g/mol

Therefore mass of barium phosphate = 0.0243 moles × 601.93 g/mol = 14.6 g of barium phosphate

For sodium metal

3 moles of barium yields 6 moles of sodium metal

0.0728 moles of barium yields 0.0728 × 6 / 3 = 0.1456 moles of sodium

Molar mass of sodium metal= 23 gmol-1

Mass of sodium metal= 0.1456g × 23 gmol-1 = 3.35 g of sodium metal

4 0
3 years ago
Ca(OH)2 (s) precipitates when a 1.0 g sample of CaC2(s) is added to 1.0 L of distilled water at room temperature. If a 0.064 g s
Nina [5.8K]

Answer:

D) Ca(OH)₂ will not precipitate because Q <  Ksp

Explanation:

Here we have first a chemical reaction in which Ca(OH)₂  is produced:

CaC₂(s)  + H₂O ⇒ Ca(OH)₂ + C₂H₂

Ca(OH)₂  is slightly soluble, and depending on its concentration it may precipitate out of solution.

The solubility product  constant for Ca(OH)₂  is:

Ca(OH)₂(s) ⇆ Ca²⁺(aq) + 2OH⁻(aq)

Ksp = [Ca²⁺][OH⁻]²

and the reaction quotient Q:

Q = [Ca²⁺][OH⁻]²

So by comparing Q with Ksp we will be able to determine if a precipitate will form.

From the stoichiometry of the reaction we know the number of moles of hydroxide produced, and since the volume is 1 L the molarity will also be known.

mol Ca(OH)₂ = mol CaC₂( reacted = 0.064 g / 64 g/mol = 0.001 mol Ca(OH)₂

the concentration of ions will be:

[Ca²⁺ ] = 0.001 mol / L 0.001 M

[OH⁻] = 2 x 0.001 M  = 0.002 M  ( From the coefficient 2 in the equilibrium)

Now we can calculate the reaction quotient.

Q=  [Ca²⁺][OH⁻]² = 0.001 x (0.002)² = 4.0 x 10⁻⁹

Q < Ksp since 4.0 x 10⁻⁹ < 8.0 x 10⁻⁸

Therefore no precipitate will form.

The answer that matches is option D

8 0
3 years ago
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