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netineya [11]
2 years ago
14

1. Calculate the average atomic mass of rubidium. Rubidium has two isotopes, 85Rb and 87Rb. 85Rb has an atomic mass of 84.912 am

u and occurs at an abundance of 72.17%. 87Rb has an atomic mass of 86.909 amu and occurs at an abundance of 27.83%. Show your work
Chemistry
1 answer:
DiKsa [7]2 years ago
5 0
Just use labels I’m lazy

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Elements occur in a number of isotopic forms. In this problem, you will learn about the notation used to distinguish different i
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  • <em>Number of protons, Z = 14</em>
  • <em>Number of neutrons, N = 14</em>

Explanation:

<u>1) About isotopes:</u>

<em>Isotopes</em> are different kind of atoms of the same element. Hence, they have the atomic number (Z), which is the number of <em>protons</em>, the same number of electrons (talking about to neutral atoms, not ions), and different <em>number of neutrons N).</em>

This is, it is the number of neutrons what distinguish different isotopes of an element.

<u>2) About the notation used to distinguish different isotopes:</u>

A superscript and a subscript, both to the left of the chemical symbol of the element, are used to <em>distinguish different isotopes</em>:

       A ←------------- This superscript tells the mass number of the isotope

           X ←--------- This is the chemical symbol of the element

      Z ←-------------- This subscript is the atomic number of isotope

In our case, the notiation for the isotope of silicon is:  ²⁸₁₄ Si

So, we have:

  • 28 is the mass number (A)
  • 14 is the atomic number (Z)
  • Si is the chemical symbol.

Now, you can answer the questions of the <em>part A</em>:

  • Number of protons: Z = 14
  • Number of neutrons N:

       mass number = number of protons + number of neutrons

                   A         =                 Z              +                N

⇒ N = A - Z = 28 - 14 = 14

In <u>conclusion</u>:

  • Number of protons, Z = 14
  • Number of neutrons, N = 14
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