Answer:
<u>167.2 g</u>
Explanation:
Known
VC4H10 = 21.3
T = 0.00 C (convert to Kelvin: 273 K)
P = 1.00 atm
Unknown
m = ?g
1. <u>Write the balanced chemical equation</u>
1 C4H10 + 1O2 -----> 4 CO2 + 5 H2O
2. <u>Find the volume ratio of Carbon Dioxide to Butane </u>
1 C4H10 4 CO2 = 4 volumes CO2 / 1 volume C4H10
3.<u> Multiply by the known volume of n (butane)</u>
21.3 L C4H10 x 4 volumes CO2 / 1 volume C4H10 = 85.2 L C4H10
4. <u>Use ideal gas law</u>
PV = nRT solve for n ----> n = PV/RT
n= (1.00 atm) (85.2 L) / (0.0821 L atm/mol K) (273) = 3.80 mol CO2
5.<u> Find molar mass of CO2</u>
1 C x 12 + 2 O x 16 = 44.00
6. <u>Multiply the ideal gas law solution (3.80) by molar mass CO2 (44.00)</u>
3.80 mol CO2 x 44.00 g CO2
= 167.2 g CO2
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Answer:
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Explanation:
Answer:
Mass = 72.52 g
Explanation:
Given data:
Mass of hydrogen phosphate produced = ?
Mass of P₂O₅ react = 105.9 g
Solution:
Chemical equation:
P₂O₅ + 3H₂O → 2H₃PO₄
Number of moles of P₂O₅:
Number of moles = mass/molar mass
Molar mass of P₂O₅ 283.9 g/mol
Number of moles = 105.9 g/ 283.9 g/mol
Number of moles = 0.37 mol
Now we will compare the moles of P₂O₅ with H₃PO₄ from balance chemical equation.
P₂O₅ : H₃PO₄
1 : 2
0.37 : 2/1×0.37= 0.74 mol
Mass of H₃PO₄ :
Mass = number of moles × molar mass
Mass = 0.74 mol × 98 g/mol
Mass = 72.52 g
Sedimentary Rocks.
The other types of rocks are igneous, formed by magma, and metamorphic, formed from other rocks changed through heat and pressure.
