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nikdorinn [45]
1 year ago
5

Selective Uptake and Gas Transport in Chemically Modified PIMs

Chemistry
1 answer:
Delvig [45]1 year ago
3 0

Selective uptake is the procedure with the aid of using which membranes in cells decide what molecules can cross in and what molecules can exit of a cell.

The studies aimed to expand chemically changed PIM-1s to be used in adsorption and fueloline separation processes. In particular, the nitrile institution in PIM-1 became transformed to numerous one of a kind purposeful organizations to control the interplay capacity of PIM-1 with one of a kind species. Synthesis of PIM-1 became done with the aid of using one of a kind methods, the usage of each the low (72h, 65 °C) and the excessive temperature (forty min, 160 °C) methods.

The response led to a aggregate of hydrolysis products. The composition of the polymer has a profound impact at the very last overall performance of the polymer. Powder samples of hydrolysed PIMs had been used withinside the studies. The discount of nitrile to number one amine became done the usage of borane dimethyl sulphide complex, ensuing in amine PIM-1.

Read more about transport;

brainly.com/question/24925498

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In the experiment, you added water to the reaction vessel after the reaction was complete, but we did not discuss why. Based on
chubhunter [2.5K]

Answer:

A.

Explanation:

Water was added to the reaction after the completion of the reaction so as to lower the solubility if the product in the solution therefore, the product can be precipitated out. On adding water the reaction moves in forward direction and more product is formed. (By Le Chatelier's principle). Thus, the precipitation occurs. Hence, option A is correct.

5 0
3 years ago
An aqueous solution of a certain chemical is found to boil at 104.5 oC. At what temperature is this solution likely to freeze? T
xeze [42]

Answer:

16.4 °C

Explanation:

Boiling point elevation is the phenomenon in which the boiling point of a solvent will increase when another compound is added to it; meaning that athe resultant solution has a higher boiling point than its pure solvent.

Using the ebullioscopic constant,

ΔT = m * i * Kb

Where,

Δ T is the temperature difference between the boiling point of the solution, Temp.f and boiling point of the pure solvent, Temp.i

Kb is the ebulliscope factor of water = 0.510 °C.kg/mol

i is the van hoffs number = 1

m is the molality in mol/kg.

Calculating the molality of the solution,

Temp.i = 100°C

Temp.f = 104.5 °C

= 4.5/(1*0.510)

= 8.8235 mol/kg

Freezing point depression is defined as the decrease in the freezing point of a solvent on the addition of a solute.

Using the same equation, but kf = 1.86 °C.kg/mol

ΔT = m * i * Kf

Temp.i = freezing point of water = 0°C

Temp.f = (8.8235*1.86) - 0

= 16.412 °C

Freezing point of the solution = 16.4 °C

3 0
3 years ago
= 25 X 5 = (use the correct number of sig figs)
Anton [14]

Answer:

1.25 *10^2

Explanation:

25*5 = 125

= 1.25 *10^2

5 0
3 years ago
The process of fermentation involves chemical reactions that convert solid glucose (C6H12O6) into aqueous ethanol and carbon dio
e-lub [12.9K]

Answer:

C6H12O6 —> 2C2H5OH + 2CO2

Explanation:

The equation for the reaction is given below:

C6H12O6 —> C2H5OH + CO2

We can balance the equation above as follow:

There are 12 atoms of H on the left side and 6 atoms of the right side. It can be balance by putting 2 in front of C2H5OH as shown below:

C6H12O6 —> 2C2H5OH + CO2

There are 6 atoms of C on the left side and 5 atoms on the right side. It can be balance by putting 2 in front of CO2 as shown below:

C6H12O6 —> 2C2H5OH + 2CO2

Now the equation is balanced.

4 0
3 years ago
The boiling point of methanol is 64 7°C. Its melting point is -976°C. At room temperature (-25°C), methanol is in which state?
marissa [1.9K]

At -25 °C, methanol, whose boiling point is 64.7 °C and its melting point is -97.6 °C, is in the liquid state.

The melting point is the temperature at which a substance passes from solid to liquid. Below the melting point, a substance is in the solid state. Above the melting point, a substance is in the liquid or gas state.

The boiling point is the temperature at which a substance passes from liquid to gas. Below the boiling point, a substance is solid or liquid. Above the boiling point, a substance is in the gas state.

At -25 °C, methanol is above the melting point (-97.6 °C) and below the boiling point (64.7 °C). Thus, it is in the liquid state.

At -25 °C, methanol, whose boiling point is 64.7 °C and its melting point is -97.6 °C, is in the liquid state.

You can learn more about the melting and boiling points here: brainly.com/question/5753603?referrer=searchResults

3 0
2 years ago
Read 2 more answers
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