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nikdorinn [45]
1 year ago
5

Selective Uptake and Gas Transport in Chemically Modified PIMs

Chemistry
1 answer:
Delvig [45]1 year ago
3 0

Selective uptake is the procedure with the aid of using which membranes in cells decide what molecules can cross in and what molecules can exit of a cell.

The studies aimed to expand chemically changed PIM-1s to be used in adsorption and fueloline separation processes. In particular, the nitrile institution in PIM-1 became transformed to numerous one of a kind purposeful organizations to control the interplay capacity of PIM-1 with one of a kind species. Synthesis of PIM-1 became done with the aid of using one of a kind methods, the usage of each the low (72h, 65 °C) and the excessive temperature (forty min, 160 °C) methods.

The response led to a aggregate of hydrolysis products. The composition of the polymer has a profound impact at the very last overall performance of the polymer. Powder samples of hydrolysed PIMs had been used withinside the studies. The discount of nitrile to number one amine became done the usage of borane dimethyl sulphide complex, ensuing in amine PIM-1.

Read more about transport;

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Liono4ka [1.6K]

Answer:

d and e - Sodium and antimony

Explanation:

The atomic numbers remain the same, while the mass numbers change (because neutrons are being added or taken away).

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What will the charge oxidiation state be for boron
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3+

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For each of the following compounds, state whether it is ionic or covalent, and if it is ionic, write the symbols for the ions i
kupik [55]

Answer :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

For the given options:

Option A:  KClO_4

This compound is formed by the combination of potassium, K^+ which is a metal and ClO_4^- ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option B:  Mg(C_2H_3O_2)_2

This compound is formed by the combination of magnesium, Mg^{2+} which is a metal and C_2H_3O_2^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

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Hydrogen and sulfur, both are non-metals and they will form a covalent compound.

Option D:  Ag_2S

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Option E:  N_2Cl_4

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6 0
3 years ago
The standard cell potential of the following galvanic cell is 1.562 V at 298 K. Zn(s) | Zn2+(aq) || Ag+(aq) | Ag(s) What is the
myrzilka [38]

Answer:

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Explanation:

Use the Nernst Equation => E(non-std) = E⁰(std) – (0.0592/n)logQc …

             Zn⁰(s) => Zn⁺²(aq) + 2 eˉ

2Ag⁺(aq) + 2eˉ=> 2Ag⁰(s)          

_____________________________

Zn⁰(s) + 2Ag⁺(aq) => Zn⁺²(aq) + 2Ag(s)

Given E⁰ = 1.562v

Qc = [Zn⁺²(aq)]/[Ag⁺]² = (1 x 10ˉ³)/(0.150)² = 0.044

E = E⁰ -(0.0592/n)logQc = 1.562v – (0.0592/2)log(0.044) = 1.602v

4 0
3 years ago
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