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3 years ago

In examples where the volume of a system is under constant pressure, which of

1 answer:

6 0

Answer:

D

Explanation:

At constant volume, the heat of reaction is equal to the change in the internal energy of the system. ... Most chemical reactions occur at constant pressure, so enthalpy is more often used to measure heats of reaction than internal energy.

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Question 1 (1 point)

ladessa [460]

Answer:D - adding a catalyst

Explanation:

4 0

2 years ago

1. How many grams would 8.1 x 1021 molecules of sucrose (C12H22011)<br> weigh?

Nimfa-mama [501]

Answer:

Mass = 4.6 g

Explanation:

Given data:

Number of molecules of sucrose = 8.1 ×10²¹ molecules

Mass of sucrose = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules

1.35 × 10⁻² mol

Mass of sucrose:

Mass = number of moles × molar mass

Molar mass = 342.3 g/mol

Mass = 1.35 × 10⁻² mol ×342.3 g/mol

Mass = 462.1 × 10⁻² g

Mass = 4.6 g

7 0

3 years ago

CAN SOMEONE PLEASE HELP!

katrin [286]

Answer:C

Explanation: they break apart into ions as they dissolve into solution this process is known as dissociation.

3 0

1 year ago

Read 2 more answers

How many oxygen atoms are in the product of this balanced chemical equation

svlad2 [7]

Answer:

two oxygen atoms

There are two oxygen atoms in the reactants and two atoms of oxygen in the product.

Explanation:

8 0

2 years ago

How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant

schepotkina [342]

Answer:

1.8 × 10² s

Explanation:

Let's consider the reduction that occurs upon the electroplating of copper.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We will establish the following relationships:

1 g = 1,000 mg
The molar mass of Cu is 63.55 g/mol
When 1 mole of Cu is deposited, 2 moles of electrons circulate.
The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
1 A = 1 C/s

The time that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

$336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s$

3 0

2 years ago