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3 years ago

In examples where the volume of a system is under constant pressure, which of

1 answer:

6 0

Answer:

D

Explanation:

At constant volume, the heat of reaction is equal to the change in the internal energy of the system. ... Most chemical reactions occur at constant pressure, so enthalpy is more often used to measure heats of reaction than internal energy.

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A sample of aspirin weighing 5.945 g became contaminated with 2.134 g of sodium sulfate. The resulting

ira [324]

Answer:

The correct answer to the following question will be "62.9 %".

Explanation:

The given values are:

The aspirin's initial amount = 5.945 g.

and is polluted containing 2,134 g of sodium sulfate.

After extraction we provided 3,739 g of pure aspirin.

Now,

$Percentage \ of \ recovery \ aspirin =\frac{Aspirin \ amount \ isolated \ after \ extraction}{initial \ amount \ of \ aspirin}\times 100$

On putting the values in the above formula, we get

⇒ $=\frac{3.739}{5.945}\times 100$

⇒ $=62.9 \ percent$

Note: percent = %

7 0

2 years ago

Atmospheric pressure yesterday was given as 0.875 atm. Express this pressure in units of torr and also in kilopascals (kPa), res

Aneli [31]

This problem is about conversion and dimensional analysis. Important information to know:
1 atm = 760 torr = 101.325 kPa

For atm to torr conversion:

0.875 atm * (760 torr / 1 atm) = 665 torr

For atm to kPa conversion:

0.875 atm * (101.325 kPa / atm) = 88.7 kPa

Thus the answer is b) 665 torr and 88.7 kPa

5 0

3 years ago

2Na(s) + Cl2(g) - 2NaCl(s) + 822 kj

pychu [463]

Answer:

Is there any other part to this question? If not I'm pretty sure the answer is 205.5 kJ

Explanation:

8 0

2 years ago

Read 2 more answers

Which of the substances are elements please help

ivanzaharov [21]

Answer:

Substances 1 and 2

Explanation:

an element only has 1 kind of atoms :3

6 0

3 years ago

For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.

Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0

3 years ago