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3 years ago

How are elements with atomic masses greater than Uranium’s made?

Chemistry

1 answer:

JulsSmile [24]3 years ago

7 0

Atoms heavier that uranium do not exist in nature.they must be synthesized in a particle accelerator.

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Calculate the energy required to produce 6.0 moles of Cl2O7 using the following reaction 2 Cl2 + 7 O2 + 130kcal -> 2 Cl207

PilotLPTM [1.2K]

Answer:

455 Kcal

Explanation:

2Cl2(g) + 7O2(g) + 130kcal → 2Cl2O7(g)

Rearranging we get,

2Cl2(g) + 7O2(g) → 2Cl2O7(g) Δ H = 130 kcal . mol⁻¹

So for per mol reaction will be as above.

In case of 7 mols of product, we need 7/2 mole ratio x 130 = 455 Kcal

5 0

2 years ago

How many moles of O2 should be supplied to burn 1.82 mol of C3H8 (propane) molecules In a camping stove?

pashok25 [27]

C3H8 + 5O2 ------> 3CO2 + 4H2O

from reaction 1 mol 5 mol

given 1.82 mol x mol

x=(1.82*5)/1 = 9.10 mol CO2

4 0

3 years ago

After distilling your crude methyl benzoate, you set aside 4.83 grams of the purified ester. You then prepare the grignard reage

Ber [7]

Answer:

95.6 %

Explanation:

For this question, we will have 2 reactions, the formation of the grignard reagent and the formation of the alcohol. The first step then is the calculation of the maximum amount of the grignard reagent. For this, we have to convert the grams to moles and check the smallest value. To do this we have to take into account the following conversion ratios:

Molar mass of Mg = 24 g/mol

Molar mass of phenylmagnesium bromide ( $C_6H_5Br$ )= 157 g/mol

Density of bromobenzene= 1.5 g/mL

Molar ratio between Mg and $C_6H_5Br$ = 1:1

$2.3~g~Mg\frac{1~mol~Mg}{24~g~Mg}=0.096~mol~Mg$

$9.45~mL~\frac{1g}{1.5mL}\frac{1~mol~C_6H_5Br}{157~g}=0.0402~mol~C_6H_5Br$

The smallest value is the mol of bromobenzene therefore 0.0402 mol of phenylmagnesium bromide would be produced.

The next step is repite the same steps for the reaction of formation of the alcohol. Therefore we have to find the moles of methyl benzoate, so:

Molar mass of methyl benzoate: 136.14 g/mol

$4.83~g~\frac{1~mol}{136.14~g}=0.35~mol$

The we have to divide by the coefficient of each reactive in the balance reaction. So:

$\frac{0.35~mol}{1}=0.35$

$\frac{0.0402~mol}{2}=0.0201$

Therefore the limiting reagent would be the phenylmagnesium bromide. Now, the molar ratio between the phenylmagnesium bromide and triphenyl carbinol is 2:1, so the amount of alcohol produced is 0.0201 mol triphenyl carbinol. The next step is the conversion from mol to grams of triphenyl carbinol:

Molar mass of triphenyl carbinol= 260.33 g/mol

$0.0201~mol\frac{260.33~g}{1~mol}=5.23~g~triphenyl carbinol$

Finally, we have to divide the obtanied solid by the calculated one:

$Percentage=\frac{5}{5.23}*100=95.6\%$

5 0

3 years ago

22 °C to K (approximate room temperature)

marta [7]

Answer:

295.15 i think

Explanation:

6 0

3 years ago

If an atom contains more electrons than protons, it is a action, an anion, or electrically neutral

barxatty [35]

Electrons hold a negative charge, and anion refers to a negatively charged atom.

The answer is anion. Here's a way to help remember:

Cats have paws, and cations are "paws"itive (positive).

6 0

3 years ago