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Nostrana [21]
3 years ago
15

What is the measure of an angle if the measures of its two adjacent supplementary angles add up to 100°?

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0
<h3>Answer:  130</h3>

Explanation:

Let x be the unknown angle we want to find.

Let y be adjacent and supplementary to x. This means x+y = 180

Let z also be adjacent and supplementary to x. So x+z = 180 also

Subtracting the two equations leads to y-z = 0 and y = z. So effectively we've proven the vertical angle theorem.

Since the supplementary angles to x add to 100, we know that y+z = 100. Plug in y = z and solve for z

y+z = 100

z+z = 100

2z = 100

z = 100/2

z = 50

Therefore,

x+z = 180

x+50 = 180

x = 180-50

x = 130

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The Original Price is $40

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50 1 20
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How many solutions does 2x+2-3x=3x-4
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Answer:

1 solution (x = 1.5)

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2x + 2 - 3x = 3x - 4

First, combine like terms

2 - x = 3x - 4

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4 0
2 years ago
Read 2 more answers
The equation 4(x – 3)2 – 5 = 139 has two solutions: one positive and one negative. What is the
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Answer:

Step-by-step explanation:

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3 0
3 years ago
Anyone willing to help? Surprise included
AveGali [126]

Answer:

An arithmetic sequence has a constant difference between each term.

For example: 2,4,6,8,10,12,…

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We call this the common difference, d.

A geometric sequence has a constant ratio (multiplier) between each term.

An example is: 2,4,8,16,32,…

So to find the next term in the sequence we would multiply the previous term by 2.

This is called the common ratio, r.

These sequences are closely related as they both have the same first term, but I hope you can see how different they become if they have a common difference or a common ratio.

We can create a decreasing arithmetic sequence by choosing a negative common difference.

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Step-by-step explanation:

4 0
3 years ago
If you can solve it.Thanks in advance
vivado [14]

Answer:

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Step-by-step explanation:

we have

f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}

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we know that

In the function

f(g(x))

The variable of the function f is now the function g(x)

substitute

f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}

f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}

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