Answer:
Electrons
Explanation:
Atoms both have negative and positive particles
Protons are positive
Electrons are negative
Neutrons are neutral
Nuclei is where you find both neutrons and protons in an atom
Bonds payable to whomever holds them are called bearer bonds or unregistered bonds.
<h3>What is bearer bond ?</h3>
Bonds that have no registered owners are known as bearer bonds. Instead, the bond is owned by whoever "bears" (or has possession of) it. Bearer bonds, sometimes known as coupons, have coupons that bondholders can detach and present to receive interest payments.
<h3>What are interest payments ?</h3>
An interest rate is the amount of interest that is payable each period stated as a percentage of the amount that was lent, deposited, or borrowed. The principal amount, interest rate, frequency of compounding, and duration of the loan, deposit, or borrowing determine the total amount of interest on a sum that was lent or borrowed.
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Answer:
The assumption is quite reasonable.........
A lightbulb contains Ar gas at a temperature of 295K and at a pressure of 75kPa. The light bulb is switched on, and after 30 minutes its temperature is 418 K. What is a numerical setup for calculating the pressure of the gas inside the light bulb at 418K?
Explanation:
P
1
T
1
=
P
2
T
2
given constant
n
, and constant
V
, conditions that certainly obtain with a fixed volume light bulb.
And so
P
2
=
P
1
T
1
×
T
2
=
75
⋅
k
P
a
295
⋅
K
×
418
⋅
K
≅
100
⋅
k
P
a
.
Had the light bulb been sealed at normal pressure during its manufacture, what do you think might occur when it is operated?
Answer: 
at the temperature of the experiment is 0.56.
Explanation:
Moles of 
= 0.35 mole
Moles of 
= 0.40 mole
Volume of solution = 1.00 L
Initial concentration of = 
Initial concentration of = 
Equilibrium concentration of = 
The given balanced equilibrium reaction is,
Initial conc. 0.35 M 0.40 M 0 M 0M
At eqm. conc. (0.35-x) M (0.40-x) M (x) M (x) M
Given: (0.35-x) = 0.19
x= 0.16 M
The expression for equilibrium constant for this reaction will be,
![K_{eq}=\frac{[CO_2]\times [H_2]}{[CO]\times [H_2O]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BCO_2%5D%5Ctimes%20%5BH_2%5D%7D%7B%5BCO%5D%5Ctimes%20%5BH_2O%5D%7D)
Now put all the given values in this expression, we get :
Thus at the temperature of the experiment is 0.56.
