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Mekhanik [1.2K]
3 years ago
5

Describe a situation in your life when you might see the ideal gas law exhibited.

Chemistry
1 answer:
statuscvo [17]3 years ago
8 0

Answer:

The ideal gas law is expressed mathematically by the ideal gas equation as follows;

P·V = n·R·T

Where;

P = The gas pressure

V = The volume of the gas

n = The number of moles of the gas present

R = The universal gas constant

T = The temperature of the gas

A situation where the ideal gas law is exhibited is in the atmosphere just before rainfall

The atmospheric temperature of the area expecting rainfall drops, (when there is appreciable blockage of the Sun's rays by cloud covering) followed by increased wind towards the area, which indicates that the area was in a state of a low pressure, 'P', and or volume, 'V', or a combination of both low pressure and volume P·V

When the entry flow of air into the area is observed to have reduced, the temperature of the air in the area is simultaneously sensed to have risen slightly, therefore, the combination of P·V is seen to be proportional to the temperature, 'T', and the number of moles of air particles, 'n' in the area

Explanation:

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Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
galben [10]

The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

PV = nRT

1.5 × 12 = n × 0.0821 × 280

18 = n × 22.988

Divide both side by 22.988

n = 18 / 22.988

n = 0.783 mole

Next, we shall determine the mole of NaCl needed for the reaction.

F₂ + 2NaCl —> Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.

Finally, we shall determine the mass of 1.566 moles of NaCl.

  • Mole = 1.566 moles
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

6 0
2 years ago
PLEASEEE HELPPP I SUCK AT CHEM :(
Luda [366]

Answer:

a) H2SO4 + 2KOH -> 2H2O + K2SO4

b) 9.809 ml

Explanation:

Number of Moles = Mass/ Molar Mass

Therefore: Mass = Number of moles * Molar Mass

--------------------------------------------

Molar mass of H2SO4:

H2= 2.02

S= 32.07

O4= 64

--------------------------------------------

H2SO4 has the molar mass of 98.09

--------------------------------------------

the Moles of H2SO4 is given to be 0.100M

Therefore:

Mass= 98.09*0.1

          = 9.809g

---------------------------------------------------

Assuming that 1 g= 1 ml, the volume of sulfuric acid is 9.809 ml.

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3 years ago
How many significant figures are in 1.00 L
likoan [24]

Answer:

3 significant numbers

6 0
3 years ago
Can U help me fill in the blank pls !!
KonstantinChe [14]

Answer:

Molecules, arranged, cube

Explanation:

These are possible answers.

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3 years ago
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