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3 years ago

Describe a situation in your life when you might see the ideal gas law exhibited.

Chemistry

1 answer:

statuscvo [17]3 years ago

8 0

Answer:

The ideal gas law is expressed mathematically by the ideal gas equation as follows;

P·V = n·R·T

Where;

P = The gas pressure

V = The volume of the gas

n = The number of moles of the gas present

R = The universal gas constant

T = The temperature of the gas

A situation where the ideal gas law is exhibited is in the atmosphere just before rainfall

The atmospheric temperature of the area expecting rainfall drops, (when there is appreciable blockage of the Sun's rays by cloud covering) followed by increased wind towards the area, which indicates that the area was in a state of a low pressure, 'P', and or volume, 'V', or a combination of both low pressure and volume P·V

When the entry flow of air into the area is observed to have reduced, the temperature of the air in the area is simultaneously sensed to have risen slightly, therefore, the combination of P·V is seen to be proportional to the temperature, 'T', and the number of moles of air particles, 'n' in the area

Explanation:

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1 year ago

At a certain temperature, 0.900 mol of SO3 is placed in a 2.00-L container.

Goryan [66]

Answer:

Kc = 2.34 mol*L

Explanation:

The calculation of the Kc of a reaction is performed using the values of the concentrations of the participants in the equilibrium.

A + B ⇄ C + D

Kc = [C] * [D] / [A] * [B]

According to the reaction

Kc = [SO2]^2 * [O2]^2 / [SO3]^2

Knowing the 0.900 mol of SO3 is placed in a 2.00-L it means we have a 0.450 mol/L of SO3

0.450 --> 0 + 0 (Beginning of the reaction)

0.260 --> 0.260 + 0.130 (During the reaction)

0.190 --> 0.260 + 0.130 (Equilibrium of the reaction)

Kc = [0.260]^2 + [0.130]^2 / [0.190]^2

Kc = 2.34 mol*L

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3 years ago