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Elis [28]
3 years ago
5

Timothée Chalamet is hot

Chemistry
2 answers:
Elza [17]3 years ago
8 0
False. harry styles all the way
makvit [3.9K]3 years ago
4 0

Answer:

True

Explanation:

In my opinion, LOL

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What mass of carbon dioxide gas occupies a volume of 81.3L at 204 kPa and a temperature of 95.0°C?
alexandr1967 [171]

Answer:

236.9g

Explanation:

Given parameters:

Volume of gas  = 81.3L

Pressure of gas = 204kPa

temperature of gas = 95°C

Unknown:

Mass of carbondioxide gas = ?

Solution:

To solve this problem, the ideal gas law will be well suited. The ideal gas law is a fusion of Boyle's law, Charles's law and Avogadro's law.

Mathematically, it is expressed as;

                    PV = nRT

the unknown here is n which is the number of moles;

P is the pressure, V is the volume, R is the gas constant and T is the temperature.

convert pressure into atm

               101.325KPa  = 1atm

             204 kPa = \frac{204}{101.325}   = 2atm

Convert temperature to Kelvin;   95 + 273  = 368K

       2 x 81.3 = n x 0.082 x 368

             n = \frac{2 x 81.3}{0.082 x 368}   = 5.38moles

Since the unknown is mass;

 Mass  = number of moles x molar mass

      Molar mass of carbon dioxide  = 12 + 2(16)  = 44g/mol

 Mass  = 5.38 x 44  = 236.9g

5 0
3 years ago
A sample of oxygen gas has a volume of 45.8 mL when its pressure is 0.492 atm. What
White raven [17]

Answer:

<h2> a. 23.6</h2>

Explanation:

P_1=0.492\:atm\\V_1 = 45.8\:ml\\V_2 = ?\\P_1 = 0.954\:atm\\\\Boyle's Law = P_1V_1 = P_2V_2\\\\Lets \:make\: V \:subject\:of\:the\:formula\\\\\frac{P_1V_1}{P_2} = \frac{P_2V_2}{P_2} \\ \\V_2 =\frac{P_1V_1}{P_2} \\V_2 = \frac{0.492\times45.8}{0.954}\\ \\V_2 = \frac{22.5336}{0.954} \\\\V_2  = 23.620\\\\V_2 = 23.6

4 0
3 years ago
Read 2 more answers
To test the purity of sodium bicarbonate, you dissolve a 3.50g sample in water and add sulfuric acid. if 1.04g of carbon dioxide
Andrews [41]

Answer is: the percent purity of the sodium bicarbonate is 56.83 %.

1. Chemical reaction: 2NaHCO₃ + H₂SO₄ → 2CO₂ + 2H₂O + Na₂SO₄.

2. m(NaHCO₃) = 3.50 g

n(NaHCO₃) = m(NaHCO₃) ÷ M(NaHCO₃).

n(NaHCO₃) = 3.50 g ÷ 84 g/mol.

n(NaHCO₃) = 0.042 mol.

3. From chemical reaction: n(NaHCO₃) : n(CO₂) = 1 : 1.

n(CO₂) = 0.042 mol.

m(CO₂) = 0.042 mol · 44 g/mol.

m(CO₂) = 1.83 g.

4. the percent purity = 1.04 g/1.83 g  ·100%.

the percent purity = 56.8 %.

8 0
3 years ago
What does the second law of thermodynamics say about entropy
alukav5142 [94]

Answer:

The entropy and the systems surrounding it tend to increase.

5 0
2 years ago
Read 2 more answers
How many nitrogen atoms are in 4AgNO3
tensa zangetsu [6.8K]

Answer:

Silver/AG= 4

Nitrogen/N=4

Oxygen/O=12

Explanation:

6 0
2 years ago
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