All categories

3 years ago

why do chemist use relative masses of atoms compared to a refference isotope rather than the actual of the atoms

Chemistry

1 answer:

Maksim231197 [3]3 years ago

5 0

It's as simple as the actual masses of atoms are very small and difficult to work with, that's all.

To expand...

I think logically, it would make sense to use the mass of the individual atoms as your result would be more precise or "true", but practically it would be extraordinarily hard to do.

Relative atomic masses are compared to the Carbon-12 isotope and averaged which is important. The values have been averaged and so in calculations the difference between using relative atomic mass and the actual masses of the atoms will be small. Relative atomic mass accounts for not knowing the mass all atoms as your relative atomic mass is the average mass of the isotopes in a naturally occurring sample of the element, taking into account the proportion of each isotope present.

You might be interested in

Which substance may lower air temperatures after a volcanic eruption? lava O sulfur dioxide O carbon dioxide O water vapor

IrinaVladis [17]

I think it’s sulfur dioxide

8 0

3 years ago

Read 2 more answers

What is the only letter not appearing on the periodic table?.

ivolga24 [154]

Answer:

The answer is j

Explanation:

3 0

2 years ago

The pressure in a car tire is 198 kPa at 27°C. After a long drive, the pressure

AlekseyPX

Answer : The temperature of the air in the tire is, 341 K

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$

or,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1$ = initial pressure = 198 kPa

$P_2$ = final pressure = 225 kPa

$T_1$ = initial temperature = $27^oC=273+27=300K$

$T_2$ = final temperature = ?

Now put all the given values in the above equation, we get:

$\frac{198kPa}{300K}=\frac{225kPa}{T_2}$

$T_2=340.9K\approx 341K$

Therefore, the temperature of the air in the tire is, 341 K

5 0

3 years ago

What kind of properties can only be observed when a substance changes into a different substance?

Shkiper50 [21]

<h3>Answer:</h3><h2>Chemical properties</h2><h3>Explanation:</h3>

By its very definition, a chemical property is one which is exhibited as a result of a chemical reaction. This may happen during or after the reaction. This is because in a chemical reaction there is a transformation in the physical composition of the components and this directly affects its chemical properties.

4 0

3 years ago

A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4

natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

$M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M$

8 0

3 years ago