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2 years ago

How many milligrams of AgNO3 is required to completely react with 81.5 mg LiOH?

Chemistry

1 answer:

BartSMP [9]2 years ago

7 0

Answer:

$m_{AgNO_3}=577.6mg$

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is first necessary to compute the moles of reacting LiOH given its molar mass:

$n_{LiOH}=81.5mg*\frac{1g}{1000mg}*\frac{1mol}{23.95g} =0.0034molLiOH$

Thus, since there is a 1:1 mole ratio between lithium hydroxide and silver nitrate (169.87 g/mol) the resulting milligrams turn out to be:

$m_{ AgNO_3}=0.0034molLiOH*\frac{1molAgNO_3}{1molLiOH} *\frac{169.87gAgNO_3}{1molAgNO_3} *\frac{1000gAgNO_3}{1gAgNO_3} \\\\m_{AgNO_3}=577.6mg$

Best regards!

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3 years ago

2131211.1994 x 102 mL<br> Scientific notation

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3 years ago

***BRAINLIEST ASNWERRR***<br>How many grams are in 34.2 moles of Lithium (Li)?

Step2247 [10]

Mass of Li = 237.38 g

<h3>Further explanation</h3>

The mole itself is the number of particles contained in a substance amounting to 6.02.10²³

$\large {\boxed {\boxed {\bold {mol = \frac {mass} {molar \: mass}}}}$

<h3>Known</h3>

Moles of Li = 34.2

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$\tt mol=\dfrac{mass}{MW}\\\\mass=mol\times MW\\\\mass=34.2\times 6,941~g/mol\\\\mass=\boxed{\bold{237.38~g}}$

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3 years ago

Assume prices increase from $15 to $18, yet quantity remains at 25. What is the total revenue?

UNO [17]

Given:

Number of items = 25

Price per item = $18

<u>To determine:</u>

The total revenue

<u>Explanation:</u>

Total revenue = quantity * price per item

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3 years ago

How much heat is released when 6.00 g of methane is combusted using the reaction below? CH4 + 2O2 ? CO2 + 2H2O ?Hrxn = -890. KJ

goblinko [34]

Answer : The amount of heat released is, -121.04 KJ

Solution : Given,

Enthalpy of reaction, $\Delta H_{rxn}$ = -890 KJ

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First we have to calculate the moles of methane.

$\text{Moles of methane}=\frac{\text{Mass of methane}}{\text{Molar mass of methane}}=\frac{6g}{44g/mole}=0.136moles$

The given balanced reaction is,

$CH_4+2O_2\rightarrow CO_2+2H_2O$

From the balanced reaction we conclude that

1 mole of methane releases heat = -890 KJ

0.136 moles of methane releases heat = $\frac{0.136moles}{1mole}\times -890KJ=-121.04KJ$

Therefore, the amount of heat released is, -121.04 KJ

8 0

3 years ago

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