How many milligrams of AgNO3 is required to completely react with 81.5 mg LiOH?
1 answer:
Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is first necessary to compute the moles of reacting LiOH given its molar mass:
Thus, since there is a 1:1 mole ratio between lithium hydroxide and silver nitrate (169.87 g/mol) the resulting milligrams turn out to be:
Best regards!
You might be interested in
The time required to reduce the concentration from 0.00757 M to 0.00180 M is equal to 1.52 × 10⁻⁴ s. The half-life period of the reaction is 9.98× 10⁻⁵s.
<h3>What is the rate of reaction?</h3>The rate of reaction is described as the speed at which reactants are converted into products. A catalyst increases the rate of the reaction without going under any change in the chemical reaction.
Given the initial concentration of the reactant, C₀= 0.00757 M
The concentration of reactant after time t is C₁= 0.00180 M
The rate constant of the reaction, k = 37.9 M⁻¹s⁻¹
For the first-order reaction:
0.00180 = 0.00757 - (37.9) t
t = 1.52 × 10⁻⁴ s
The half-life period of the reaction:
Half-life of the reaction = 9.98 × 10⁻⁵s
Learn more about the rate of reaction, here:
#SPJ1