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yaroslaw [1]
2 years ago
10

How can you tell the difference between two clear liquids

Chemistry
1 answer:
posledela2 years ago
6 0

Answer:

To identify a pure liquid substance using the physical properties of solubility, density, and boiling point. The physical properties of a pure substance can be measured without changing the composition of the substance.

Explanation:

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Please help me with chemistry!
Helga [31]

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

Explanation:

Reacting bromide (Br₂) with sodium iodine (NaI) will produce sodium bromide (NaBr) and iodine (I₂).

To balance the equation the number of atoms of each element entering the  reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)

where:

l - liquid

s - solid

This is a single replacement reaction because an element in a compound is replaced by another element. Generally a single replacement reaction is represented as: A + BC → AC + B

Learn more about:

types of chemical reactions

brainly.com/question/10105284

balancing chemical equations

brainly.com/question/13908054

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3 years ago
Which book has kinetic energy
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Where is the picture
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3 years ago
Which of the following best describes the impact of glaciers upon the surface of the earth?
Ahat [919]

Answer:

D. All of the above

Explanation:

Because all of these have something to do with how glaciers are affecting the planet.

6 0
3 years ago
A student has two substances at a lab table. One substance is iron pyrite (fool's gold) and the other is real gold. After placin
blagie [28]
The answer is A) 1 mL 
6 0
3 years ago
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Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

Squaring both sides, we get

(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}

Solve for <em>M</em>₂:

M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}

M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}

= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}

7 0
3 years ago
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