We are given the molar mass of Molybdenum as 95.94 g/mol. Also, the chemical symbol for Molybdenum is Mo. This question is asking for the amount of molecules of molybdenum in a 150.0 g sample. However, since molybdenum is a metal and it is in the form of solid molybdenum, Mo (s), it is not actual a molecule. A molecule has one or more atom bonded together. We will instead be finding the amount of atoms of Molybdenum present in the sample. To do this we use Avogadro's number, which is the amount of atoms/molecules of a substance in 1 mole of that substance.
150.0 g Mo/ 95.94 g/mol = 1.563 moles of Mo
1.563 moles Mo x 6.022 x 10²³ atoms/mole = 9.415 x 10²³ atoms Mo
Therefore, there are 9.415 x 10²³ atoms of Molybdenum in 150.0 g.
Answer:
Kc = 0.20
Explanation:
N₂O₄ ⇄ 2NO₂
moles 5.3mol 2.3mol
Vol 5L 5L
Molarity 5.3/5M 2.3/5M
= 1.06M = 0.46M
Kc = [NO₂]²/[N₂O₄] = (0.46)²/(1.06) = 0.1996 ≅ 0.20
Answer:
Promotes Stellar Formation:
-Increased Gravitational Attraction
-Higher Temperature
Does Not Promote Stellar Formation:
-Decreased Gravitational Attraction
-Lower Temperature
Explanation:
Stars need at least three million kelvins to form, and the gravitational attraction helps form the star in the first place.
