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vladimir1956 [14]
2 years ago
8

More heat is required to raise the temperature of water than any other substance. This is a description of the unique property o

f water known as _____.
Chemistry
1 answer:
Anarel [89]2 years ago
5 0

Answer:

These hydrogen bonds are responsible for some of water's unique properties: Water has a high heat capacity , which is the amount of heat that must be added to raise its temperature. Specific heat is the heat required to raise the temperature of 1 g of a substance by 1o C.

Explanation:

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During evaporation, the volume of the liquid decreases and the liquid becomes what??? ​
oee [108]

Answer:

Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor. ... Once water evaporates, it also helps form clouds

4 0
3 years ago
4.07 x 10-17<br> (5.6 x 10") (5.8 x 105)
Andrej [43]
4.07 x 10-17 = 23.7
(5.6 x 10”) (5.8 x 105)= log(100)
log(7)
Hope this helped
3 0
2 years ago
Steve traveled the first 7 hours of his
const2013 [10]

Answer:

64

Explanation:

Distance traveled in 2 hours = 2 * 40 = 80 m

Distance traveled in 3 hours = 3 * 80 = 240m

Total distance covered = 240 + 80 = 320m

Total time = 2 + 3 =5 h

Hence avg speed = total distance covered / total time taken

= 320/5 = 64mph

5 0
3 years ago
Identify the oxidizing and reducing agent in the following reaction, and determine which element is oxidized and which is reduce
erma4kov [3.2K]

Answer:

Explanation:

Fe⁺²(aq) + ClO₂(aq) → Fe⁺³(aq) + ClO₂⁻(aq)

Here oxidation number of Fe is increased from +2 to +3 , so Fe is oxidised .

The oxidation number of Cl is reduced from + 4 to +3  so Cl is reduced .

So ClO₂(aq) is oxidising agent and Fe⁺²(aq) is reducing agent .

8 0
3 years ago
A football is inflated to 12psi at 20°C What is the new pressure in the football
Radda [10]

Answer: The new pressure is 3 psi.

Explanation:

Given: P_{1} = 12 psi,         T_{1} = 20^{o}C

P_{2} = ?,          T_{2} = 5^{o}C

Formula used is as follows.

\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{12 psi}{20^{o}C} = \frac{P_{2}}{5^{o}C}\\P_{2} = \frac{12 psi \times 5^{o}C}{20^{o}C}\\= 3 psi

Thus, we can conclude that the new pressure is 3 psi.

7 0
3 years ago
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