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Lostsunrise [7]
3 years ago
8

A^5b^3/a^3 = b^11 Help

Mathematics
2 answers:
galben [10]3 years ago
7 0

Answer:

what are you trying to solve?

Vinil7 [7]3 years ago
5 0
You ok need to be like mmm you eabgshdhsjdjidjd
You might be interested in
Do any of you guys know how to solve this
Alex17521 [72]
<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span><span>=<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span></span><span>=<span><span><span>2<span>(<span>x+4</span>)</span></span><span>(<span><span><span>x^2</span>−<span>4x</span></span>+19</span>)
</span></span><span>x+4</span></span></span><span>=<span><span><span>2<span>x^2</span></span>−<span>8x</span></span>+<span>38= is the answer</span></span></span>
5 0
3 years ago
Which expression would be easier to simplify if you used the commutative property to change the order of the numbers?
In-s [12.5K]

Answer:

the 3rd one

Step-by-step explanation:

20+17=37

-1/2+(-5/2)= -3

so 37 + ( -3 ) = -3 + 37 have the same value which is 34

3 0
3 years ago
Ricardo lost 6 golf balls while playing yesterday he bought a box of twelve golf balls and lost 4 on the course today he now has
zepelin [54]
<span>Ricardo ended up with 18 golf balls. If he lost 4 on the course today, he then had 22 to start with today. This 22 total includes a box of 12 balls he bought today. This means he had 22 - 12 yesterday, making 10. Yesterday he lost 6 while playing. Ricardo had 16 balls to start with.</span>
5 0
3 years ago
Brainliest and 5 full stars. What is 20+5-39 and 5+24 -2
Nadya [2.5K]

Answer:

The answer is : 20+5-39= <u><em>-14</em></u> and 5+24-2= <u><em>27</em></u>

Hope this helps!!!!

Step-by-step explanation:

5 0
3 years ago
Solve the equation 2^(2x+1)+8=17×2^x.
myrzilka [38]
Oooh, looks fun

ok
erm
we might want to know some properties
(x^m)(x^n)=x^{m+n}
(a^b)^c=a^{bc}
if a^m=a^n where a=a, then assume m=n

2^{2x+1}=(2^{2x})(2^1)
so
(2^{2x})(2)+8=17(2^x)
(2^{2x})(2)+2^3=17(2^x)
(2^x)^2(2)+2^3=17(2^x)
minus 17*2^x both sides
(2^x)^2(2)+2^3-17(2^x)=0
use u subsitution, u=2ˣ
(u)^2(2)+2^3-17(u)=0
solve 2u^2+8-17u=0
or
2u^2-17u+8=0
ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8

2u-1=0
2u=1
u=1/2

now
u=2ˣ

8=2ˣ
2^3=2^x
3=x

and
\frac{1}{2}=2^x
2^{-1}=2^x
-1=x

x=-1 and 3
neat problem
8 0
3 years ago
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